Answer:
C
Explanation:
(c) The two cuts that are being roasted for each time-temperature combination are an example of replication.
In the question it is given that From 10 identical cuts of lamb, 2 are randomly selected to roast using each of the time-temperature combinations in the same oven. Here it is an act of copying the exact sahpe size of the lamb in all cuts, which is nothing but replication. Moreover, this replication can help in proper comparision.
Answer:it’s is part of the cell theory because they where studying cells and to see it you need a microscope
Explanation:basically in the answer area
ANSWER:
d. remains a non-zero constant.
STEP-BY-STEP EXPLANATION:
If we consider that there is no air resistance and that the horizontal component would be at x, the velocity remains a non-zero constant
M° = 2.5 kg/sec
For saturated steam tables
at p₁ = 125Kpa
hg = h₁ = 2685.2 KJ/kg
SQ = s₁ = 7.2847 KJ/kg-k
for isotopic compression
S₁ = S₂ = 7.2847 KJ/kg-k
at 700Kpa steam with S = 7.2847
h₂ 3051.3 KJ/kg
Compressor efficiency
h = 0.78
0.78 = h₂ - h₁/h₂-h₁
0.78 = h₂-h₁ → 0.78 = 3051.3 - 2685.2/h₂ - 2685.2
h₂ = 3154.6KJ/kg
at 700Kpa with 3154.6 KJ/kg
enthalpy gives
entropy S₂ = 7.4586 KJ/kg-k
Work = m(h₂ - h₁) = 2.5(3154.6 - 2685.2
W = 1173.5KW
The answer of a & b are force of cohesion and force of adhesion
Of rest two answers I don't know
