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2 years ago

Which surface has the most friction

1 answer:

4 0

Answer: Rougher surfaces have more friction between them than smoother surfaces. That's why we put sand on icy sidewalks and roads. You can't slide as far across ice with shoes as you can on the blades of skates. The rougher surface of the soles of the shoes causes more friction and slows you down. There are four types of friction: static, sliding, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest.

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If I remove the table from under the book, what will happen to the book? Think about Newton’s second law of motion. Is there an

tiny-mole [99]

Newton’s second law of motion is a dot product of mass and acceleration, if you remove the table from, under the book, gravity will act on the book and pull it downwards to the centre of the earth

Newton's Second law of motion states that "the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object."

In our case the mass of the book and the force of gravity

Learn more about Newton's Laws of motion:

brainly.com/question/10454047

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2 years ago

URGENT!

tensa zangetsu [6.8K]

Answer:

Explanation:

A weak acid and a strong base will form a basic salt.

Option A is acidic, this pH would be found in salts formed from reactions between strong acids and weak bases.

B and C are neutral or close to neutral and as such will be formed from weak acids and weak bases, or strong acids and strong bases.

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2 years ago

Read 2 more answers

Type the correct answer in each box.

Arturiano [62]

Answer:

5SiO2 + 2CaC2 = 5Si + 2CaO + 4CO2

Explanation:

balancing equations is a lot of trial and error. My strategy to approaching this equation was to get the O's balanced. After trying several combonations I found that I needed 10 O's on each side of the equation for the other elements to match up. After I balanced the O's, I balanced my C's to 4 on each side. Then I balanced my Ca's to have 2 on each side. And last but not least I balanced my Si to have 5 on each side.

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2 years ago

A 1.00 g sample of octane (C8H18) is burned in a bomb calorimeter with a heat capacity of 837J∘C that holds 1200. g of water at

lubasha [3.4K]

Answer:

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

Explanation:

Step 1: Data given

Mass of octane = 1.00 grams

Heat capacity of calorimeter = 837 J/°C

Mass of water = 1200 grams

Temperature of water = 25.0°C

Final temperature : 33.2 °C

Step 2: Calculate heat absorbed by the calorimeter

q = c*ΔT

⇒ with c = the heat capacity of the calorimeter = 837 J/°C

⇒ with ΔT = The change of temperature = T2 - T1 = 33.2 - 25.0 : 8.2 °C

q = 837 * 8.2 = 6863.4 J

Step 3: Calculate heat absorbed by the water

q = m*c*ΔT

⇒ m = the mass of the water = 1200 grams

⇒ c = the specific heat of water = 4.184 J/g°C

⇒ ΔT = The change in temperature = T2 - T1 = 33.2 - 25 = 8.2 °C

q = 1200 * 4.184 * 8.2 = 41170.56 J

Step 4: Calculate the total heat

qcalorimeter + qwater = 6863.4 + 41170. 56 = 48033.96 J = 48 kJ

Since this is an exothermic reaction, there is heat released. q is positive but ΔH is negative.

Step 5: Calculate moles of octane

Moles octane = 1.00 gram / 114.23 g/mol

Moles octane = 0.00875 moles

Step 6: Calculate heat combustion for 1.00 mol of octane

ΔH = -48 kJ / 0.00875 moles

ΔH = -5485.7 kJ/mol

The heat of combustion for 1.00 mol of octane is -5485.7 kJ/mol

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2 years ago

(Physical Science)

Vera_Pavlovna [14]

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2 years ago