Answer: 0.548J/g°C
Explanation:
Q = s × m × DeltaT
Q = Heat (J)
S = Specific Heat Capacity
M = mass (g)
DeltaT = Change in temperature (°C)
0.158Kg x 1000 = 158g
2.510J = s x 158g x (61°C-32°C)
2.510J/(158g x 29°C) = s
S = 0.54779.... J/g°C
S = 0.548 J/g°C
The mole ratio of PbO2 to water in
Pb + PbO2 +2 H2SO4 = 2PbSO4 + 2H2O is
1 :2
1 mole of Pb reacted with 1 mole of PbO2 and 2 moles of H2SO4 to form 2 moles of PbSO4 and 2 moles of H2O
therefore the mole ratio of Pbo2 to H2O is 1:2
B. Hydra, because Hydra<span>are an ideal class of </span>Cnidaria<span> to research and on which to run tests.</span>
Use PV =nRT. Rearrange it to n = PV/RT.
P = 202.6 kPa
V = 4.0L
R = 8.314 kPa*L/mol*K
T = 127 °C + 273 = 400 K
Plug it in and solve. I got 0.24 moles of H2.
The given question is incomplete. the complete question is : If 5.15 g
is dissolved in enough water to make exactly 323 ml of solution, what is the molar concentartion of nitrate ion.
Answer: The molar concentartion of nitrate ion is 0.195.
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
Given : 5.15 g of is dissolved
Volume of solution = 323 ml
where,
n= moles of solute
= volume of solution = 323 ml
As 1 M of gives 3 M of 
ions.
Thus 0.065 M of gives = 
of ions.
The molar concentartion of nitrate ion is 0.195.
