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iris [78.8K]
3 years ago
12

Iodine-131 has a half-life of 8.10 days. In how many days will 50 grams of Iodine-131 decay to one-eighth of its original amount

?
Chemistry
2 answers:
shtirl [24]3 years ago
5 0
What you need to do is find 1/8 of 50
you can just divide 50 by 8 to get 6.25
so now you have to find how many days it will take till there are 6.25 grams of iodine left
every 8.1 days its mass is split in half 
so start splitting it in half and every time you do, you add 8.1 days
50/2 =25                                               8.1
25/2 =12.5                                        +  8.1
12.5/2= 6.25                                      +8.1
now you have reached 1/8 of the original amount of Iodine-131
so to find how long it took just add 8.1+8.1+8.1
(this is the same as 8.1x3)
which equals 24.3
it will take 24.3 days for Iodine 131 to decay to 1/8  of its original mass.

(good luck on the regent if thats what your studying for :)

Murljashka [212]3 years ago
3 0
It doesn't matter what the original mass is. 1/8 is (1/2)-cubed, and 3 half-lives is 8.3 days.
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2 years ago
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torisob [31]
About 5 degrees  that is

3 0
3 years ago
Use bond energies to calculate δhrxn for the reaction. n2(g)+3cl2(g)→2ncl3(g)
Jobisdone [24]
ΔHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)

Bond enthalpies,
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According to the balanced equation,
ΣδΗ(bond breaking)  = N ≡ N x 1 + Cl - Cl x 3
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ΣδΗ(bond making)    = N - Cl x 3 x 2
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δHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)
          = 1671 kJ mol⁻¹ - 1152 kJ mol⁻¹
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3 years ago
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Easy one! giving brainly if correct​
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5 0
2 years ago
What is the mass of a 1.71-l sample of a liquid that has a density of 0.921g/ml?
Temka [501]
Hey there!:

Volume in mL :

1.71 L * 1000 => 1710 mL

Density = 0.921 g/mL

Therefore:


Mass = Density * Volume

Mass = 0.921 * 1710

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8 0
3 years ago
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