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pav-90 [236]
3 years ago
13

How do you balance an equation O2 to O3 reaction

Chemistry
1 answer:
Minchanka [31]3 years ago
4 0

3O2 ------> 2O3

6O 6O

6 atoms of O before and after reaction.

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Silicon has 14 protons and it should have at least 12 neutrons
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I've been waiting for like 10 mins. Please answer this.
Degger [83]

The answer is B. 6CO2+H2O yields C6H12O6+ 6H20.

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3 years ago
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4. Which of the following statements is true?
Aleksandr [31]

4) The answer is: Chemical reaction rates vary with the conditions of the reaction, but nuclear decay rates do not.

Differences between nuclear and chemical reactions:

1) The electrons of an atom participates in a chemical reaction and protons in nuclear reaction.

2) Chemical reactions involve the rearrangement of electrons, because there is transfer, loss, gain and sharing of electrons in chemical reactions.

3) Nuclear reactions can produce new elements, because number of protons and neutrons is changed, chemical reactions donot produce new element.

4) Chemical reactions require heat or an input of energy to occur, this is activation energy.

5) Isotopes of the same element behave differently in a nuclear reaction, because isotopes have different number of neutrons, so products of a nuclear reaction is different.

6) The answer is: nuclear change.

Transmutation is a process that involves a change in the nucleus of an atom. It can be natural or artificial.  

For example: 14/7 N + 4/2 He --> 17/8 O + 1/1 H.  

This example is the first artificial nuclear transmutation described by Rutherford in 1919.  

Artificial transmutation can be expressed by nuclear reaction:  

Target Nuclide + Bombardment Particle → New Nuclide + Ejected Particle.  


5 0
3 years ago
The protein catalase catalyzes the reaction The Malcolm Baldrige National Quality Award aims to:
Marina CMI [18]

The question is missing a part, so the complete question is as follows:

The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.

1) Calculate Rmax

The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:

Kcat = \frac{Vmax}{Et},

where:

Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate

Et is total enzyme concentration or concentration of total enzyme catalytic sites.

Calculating:

Kcat = \frac{Vmax}{Et}

Vmax = Kcat · Et

Vmax = 4×10^{7} · 1.2 × 10^{-8}

Vmax = 4.8 × 10^{-1} M

2) Calculate the initial rate of this reaction (R):

The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:

V0 = \frac{[S].(Vmax)}{KM + [S]}, where:

[S] is the substrate's concentration

KM is the Michaelis-Menten constant

Substituting [S] = 5.14 × 10^{-6}, KM = 2.5 × 10^{-4} and Vmax = 4.8 × 10^{-1}, the result is V0 = 0.478 M.

The answers are Vmax = 4.8 × 10^{-1} M and V0 = 0.478 M.

 

7 0
3 years ago
Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. D-tagatose is sugar with six carbo
Bingel [31]

Answer:

Hexose category and ketohexose category

Explanation:

The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category

Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category

Attached below is the remaining part of the solution

6 0
3 years ago
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