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fiasKO [112]
2 years ago
6

Consider the Mg2+, Cl-, K+, and Se2- ions.The four spheres below represent these four ions, scaled according to ionic size. A) M

atch each ion to its appropriate sphere. B) In terms of size, between which of the spheres would yo find the (i) Ca2+ and (ii) S2- ions?
Chemistry
2 answers:
jek_recluse [69]2 years ago
6 0

Answer:

A is  Mg^2+

B is K^+

C is Se^2-

D is Cl^-

Ca^2+ lies between  Mg^2+ and K^+

S^2-  lies between K^+ and Se^2-

Explanation:

I have attached an image of the four spheres.

Remember that, cations are smaller in size than the corresponding atom atom because the formation of a cation often involves the removal of an entire shell. Anions are larger in size than the corresponding atom because an electron is added thereby expanding the electron cloud and size of the anion.

From left to right let us designate the spheres as ABCD.

A is  Mg^2+

B is K^+

C is Se^2-

D is Cl^-

Ca^2+ lies between  Mg^2+ and K^+

S^2-  lies between K^+ and Se^2-

vazorg [7]2 years ago
3 0

Answer:(A) Mg2+,K+, Cl-, Se2-

(B) Ca2+ (space) S2-

Explanation:

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What statements?

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Classify each of the following particulate level illustrations as a representation of either a pure substance, a homogeneous mix
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Answer:

The classification and illustrations are attached in the drawing.

Explanation:

It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.

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3 years ago
An ideal gas is contained in a cylinder with a volume of 5.0x102 mL at a temperature of 30°C and a pressure of 710. Torr. The ga
Scorpion4ik [409]

Answer:

51207 torr is the new pressure of the gas

Explanation:

We can solve this question using combined gas law that states:

P1V1T2 = P2V2T1

<em>Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of the gas</em>

<em> </em>

Computing the values of the problem:

P1 = 710torr

V1 = 5.0x10²mL

T1 = 273.15 + 30°C = 303.15K

P2 = ?

V2 = 25mL

T2 = 273.15 + 820°C = 1093.15K

Replacing:

710torr*5.0x10²mL*1093.15K = P2*25mL*303.15K

3.881x10⁸torr*mL*K = P2 * 7.579x10³mL*K

P2 = 51207 torr is the new pressure of the gas

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