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3 years ago

Which of the following can be an effect of a volcanic winter? select the two correct answers

Physics

2 answers:

Marysya12 [62]3 years ago

8 0

it is B. Famine and C. Climate cooling

Umnica [9.8K]3 years ago

8 0

Answer: B. famine C. climate cooling

Volcanic winter, is a natural condition that occurs after a volcanic eruption. The volcanic ash and sulfur aerosols are released in the massive amount which covers the stratosphere layer of the atmosphere. The sulfur aerosols reflects the incoming solar radiations from the sun and absorbs the terrestrial radiations from the entire atmosphere. These processes cools the temperature of the tropospheric layer of atmosphere lying below the stratosphere. This results in harsh winter conditions.

Therefore, on the basis of above information the famine and climate cooling is the effect of a volcanic winter.

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A boy held a ball in the air what force is he applying?

Delvig [45]

Answer:

strength

Explanation:

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3 years ago

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Find the distance traveled in one back-and-forth swing by the weight of a 12 in. Pendulum that swings through a 75 degree angle.

tia_tia [17]

The distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

The period of pendulum can be calculated by

$T = 2\pi \sqrt {\dfrac Lg}$

Where,

$T$ - period

$L$ - length = 12 inches

$g$ - gravitational acceleration = $\bold {9.8\rm \ m/s^2}$

Put the values,

$T = 2\pi \sqrt {\dfrac {12}{9.8}}\\\\T = 2 \times 3.14 \times \sqrt {0.122}\\\\T = 2.191$

Now, the angular displacement of the pendulum can be calculated by,

$\theta = A\times\rm \ cos(\omega T)$

Where,

$A$ - amplitude

$\theta$ - angle = $75^o$

$\omega$ - angular displacement = $2\pi/T$ = 2.866 m

Put the values and calculate for $\omega$ ,

$75 = A\times{\rm \ cos}(2.866\times 2.191)\\\\75 =A \times cos\ 6.26\\\\A =\dfrac {75}{0.99}\\\\A = 75.75 \rm \ inches$

Therefore, the distance traveled by pendulum, in one back-and-forth swing is 75.75 inches.

To know more about Amplitude of pendulum,

brainly.com/question/14840171

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3 years ago

A mass of 0.250 kg is attached to a spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the forc

Paha777 [63]

The force constant of the spring is approximately 24.038 newtons per meter.

As we are talking about Simple Harmonic Motion. In this exercise we need to determine the Spring Constant ( $k$ ), in newtons per meter, from the equation of the Period ( $T$ ), in seconds, which is described below: