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andrey2020 [161]
3 years ago
13

How many moles of sodium chloride can react with 18.3 liters of fluorine gas at 1.2 atmospheres and 299 Kelvin?

Chemistry
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

1.79 mol.

Explanation:

  • For the balanced reaction:

<em>2NaCl + F₂ → 2NaF + Cl₂. </em>

It is clear that 2 mol of NaCl react with 1 mol of F₂ to produce 2 mol of NaF and 1 mol of Cl₂.

  • Firstly, we can get the no. of moles of F₂ gas using the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm (P = 1.2 atm).

V is the volume of the gas in L (V = 18.3 L).

n is the no. of moles of the gas in mol (n = ??? mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (299 K).

∴ no. of moles of F₂ (n) = PV/RT = (1.2 atm)(18.3 L)/(0.0821 L.atm/mol.K)(299 K) = 0.895 mol.

  • Now, we can find the no. of moles of NaCl is needed to react with 0.895 mol of F₂:

<em><u>Using cross multiplication:</u></em>

2 mol of NaCl is needed to react with → 1 mol of F₂, from stichiometry.

??? mol of NaCl is needed to react with → 0.895 mol of F₂.

∴ The no. of moles of NaCl needed = (2 mol)(0.895 mol)/(1 mol) = 1.79 mol.

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NH_{4}Cl and NaCl<br> Balanced Equation<br> Total Ionic Equation<br> Net Ionic Equation
nadya68 [22]

Answer:

Based on compounds given, NO reaction occurs

Explanation

The compounds should exchange ions to generate a driving force that pulls the reaction to completion. => Example ...

The Molecular Equation is ...

NH₄Cl(aq) + AgNO₃(aq) => NH₄NO₃(aq) + AgCl(s)

Silver chloride forms in this reaction as a solid precipitate because of its low solubility and is the 'Driving Force' of the reaction. Driving Force is a more stable compound than any on the reactant side and when formed leaves the reaction system as a solid ppt, liquid weak electrolyte (i.e., weak acid or weak base) or a gas decomposition product of a weak electrolyte.

The Ionic Equation is ...

NH₄⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) => NH₄⁺(aq) + NO₃⁻(aq) + AgCl(s)

This shows all ions from reaction plus the Driving Force of the reaction.

The Net Ionic Equation is ...

Ag⁺(aq) + Cl⁻(aq) => AgCl(s)

The Net Ionic Equation shows only those ions undergoing reaction. The NH₄⁺ and NO₃⁻ ions are 'Spectator Ions' and do not react.

Attached is a reference sheet for determining the Driving Force of a Metathesis Double Replacement Reaction. Suggest reviewing acid-base theories and the products of decomposition type reactions.

6 0
3 years ago
What is the molarity of 0.26 mol of H2SO4 dissolved in 0.3 L of solution? *
irina1246 [14]

Answer:

A

Explanation:

molarity=moles of solute/liter of solution

molarity=0.26/0.3

molarity=0.87molar

7 0
3 years ago
Please review the attachment
astra-53 [7]

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

8 0
3 years ago
Read 2 more answers
As Matter Changes States of matter does chemical composition stay the same or not
geniusboy [140]
Whether water is frozen, in a gaseous state, or is a liquid, it is still H2O. So the chemical composition does stay the same.
6 0
3 years ago
Co(g) effuses at a rate that is ______ times that of cl2(g) under the same conditions.
il63 [147K]

Answer is: the ratio of the effusion rate is 1.59 : 1.

1) rate of effusion of carbon monoxide gas = 1/√M(CO).  

rate of effusion of carbon monoxide gas = 1/√28.

rate of effusion of carbon monoxide gas = 0.189.  

2) rate of effusion of chlorine = 1/√M(Cl₂).  

rate of effusion of chlorine = 1/√70.9.  

rate of effusion of chlorine = 0.119.  

rate of effusion of carbon monoxide : rate of effusion of chlorine =

= 0.189 : 0.119 / ÷0.119.

rate of effusion of carbon monoxide : rate of effusion of chlorine = 1.59 : 1.

4 0
2 years ago
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