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gizmo_the_mogwai [7]
3 years ago
15

1. Rank the following compounds in order of decreasing acid strength using periodic trends. Rank the acids from strongest to wea

kest.
A. HCl
B. H2S
C. HBr
D. BH3
2. Without consulting the table of acid-dissociation constants, match the following acids to the given Ka1 values.
1. H2S
2. H2SO3
3. H2SO4
A. Kal = 1.7 x 10^-7
B. Kal = 1.7 x 10^-2
C. Kal = very large
Chemistry
1 answer:
Nookie1986 [14]3 years ago
7 0

Answer:

ESCALAS MAYORES (D, E, G, A, B) Porfavor necesito ayuda,te lo agradecería muchísimo!!

Es urgente

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When a warm soda can is placed in an ice chest full of ice, the soda can _______ heat and the ice _______ heat until they are bo
Svetach [21]
D because as the soda can starts to cool off the ice in turn begins to melt because the heat from the soda is being distributed on the ice and vice versa.
5 0
3 years ago
What happens when a catalyst is added to a chemical reaction that is already in progress?
Elanso [62]

Explanation:

when the catalyst is added the reaction with the lower activation energy occur

3 0
3 years ago
A sample of Ne gas has a pressure of 654 mmHg with an unknown volume. The gas has a pressure of 345 mmHg when the volume is 495m
Lemur [1.5K]

Answer:

The initial volume of Ne gas is 261mL

Explanation:

This question can be answered using Ideal Gas Equation;

However, the following are the given parameters

Initial Pressure = 654mmHg

Finial Pressure = 345mmHg

Final Volume = 495mL

Required

Initial Volume?

The question says that Temperature is constant;

This implies that, we'll make use of Boyle's law ideal gas equation which states;

P_1V_1 = P_2V_2

Where P_1 represent the initial pressure

P_2 represent the final pressure

T_1 represent the initial temperature

T_2 represent the final temperature

P_1 = 654mmHg\\P_2 = 345mmHg\\V_2 = 495mL

Substitute these values in the formula above;

654 * V_1 = 345 * 495

654V_1 = 170775

Divide both sides by 654

\frac{654V_1}{654} = \frac{170775}{654}

V_1 = \frac{170775}{654}

V_1 = 261.123853211

V_1 = 261mL (Approximated)

<em>The initial volume of Ne gas is 261mL</em>

7 0
3 years ago
12. What is the empirical formula for C10H30O5?
kramer

Answer:

Just use a text book.. So that you get the concept

5 0
3 years ago
What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?
Lerok [7]

Answer:

2.68 Liters

Explanation:

ideal gas law

PV=NRT

to get the volume

rearrange the formula

V=nRT/P

R molar gas constant is in units joules per mole kelvin :

8.314 J/(mol K) (joules per mole kelvin)

T temperature part of this is in kelvin so you have to convert the Celsius temperature to kelvin

1 Celsius is 274.15 kelvin so

83.4 Celsius is 356.55 kelvin

P pressure is in Pascal or Pa units

so you have to convert atm into Pa

1 atm is 201636.8 Pa or Pascals so

1.99 atm is 201636.8 Pa

V volume will be in cubic meters or m^3

m^3 will need to changed to liters

1 cubic meter or m^3 is 1000 liters

n amount of substance is in moles

again the rearranged formula is

V=nRT/P

(0.182*8.314*356.55)/201636.8 =

0.00267566693 cubic meters or m^3

1 cubic meter or m^3 is 1000 liters so

0.00267566693 cubic meters or m^3 times 1000 =

2.67566693 liters

4 0
2 years ago
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