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padilas [110]
3 years ago
9

A bicycle takes 8 seconds to accelerate at a constant rate from rest to a speed of 4 m/s. If the mass of the bicycle and rider t

ogether is 85 kg, what is the net force acting on the bicycle?
Physics
1 answer:
Anon25 [30]3 years ago
3 0
Force, F = ma

            F =  m(v-u)/t

Where F is force in Newtons,  m = mass in kg = 85kg, v = final velocity, = 4m/s, u = initial velocity = 0 m/s, t = time = 8 seconds.

       F  = 85 * (4 -0) /8= 42.5

     Force = 42.5 N
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How will unbalanced forces affect the speed and direction of an object
azamat

Answer:

Explanation:

Unbalanced forces will result in the presence of acceleration. The formula

F net = ma

says that if there is a net force present and the object in question has a mass, then an acceleration is present. Now acceleration is constant in this situation because nowhere does it say the acceleration is changing. If acceleration is constant then the velocity is increasing at a steady pace (think linear function!).

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Hope this helps :)

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If you peel two strips of transparent tape off the same roll and immediately let them hang near each other, they will repel each
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Answer:

1.

Firstly removing off one strip and it leaves electrons behind, so the strip becomes positively charged.

2. The roll however is not negatively charged because it is "earthed " by the hand holding it, thus excess negatives repel each other away through the hand.

3.Tearing off the next strip and once more it leaves electrons behind, the new strip is also positively charged and will repel the first strip.

4. Then, tear two strips apart and one will leave electrons behind on the other. Meaning that one strip is positive and the other is negative and they will attract each other.

5 0
3 years ago
An 80-cm-long steel string with a linear density of 1.0 g/m is under 200 N tension. It is plucked and vibrates at its fundamenta
icang [17]

Answer:

Wavelength of the sound wave that reaches your ear is 1.15 m

Explanation:

The speed of the wave in string is

v=\sqrt{\frac{T}{\mu} }

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v=\sqrt{\frac{200}{1\times 10^{-3} }

v=447.2 m/s

Wavelength of the wave in the string is

\lambda =2L=2\times 0.8=1.6 m

The frequency is

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\lambda=\frac{v_{air}}{f} \\\lambda=\frac{344}{298.25} \\\lambda=1.15 m

8 0
3 years ago
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