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3 years ago

How can a global dependence on fossil fuels have associated social costs?

Physics

2 answers:

stiv31 [10]3 years ago

8 0

Answer:

Global dependence on fossil fuels has associated social costs.

Explanation:

Increased dependence on fossil fuels reduces their availability. When the demand is high and the availability is low, the price rises. Not every nation would then be able to afford buying fossil fuels at such high costs.

Developing and underdeveloped countries would then be left behind and only the wealthy nations would be able to afford fossil fuel purchase. This would be the immediate impact of global dependence on fossil fuels.

Fossil fuels are mainly coal, petroleum and natural gas. Since fossil fuels are non-renewable in nature over exploitation may lead to fossil fuels getting exhausted.

Papessa [141]3 years ago

7 0

Answer:

Increased dependence on fossil fuels reduces their availability. When the demand is high and the availability is low, the price rises. Not every nation would then be able to afford buying fossil fuels at such high costs.

Developing and underdeveloped countries would then be left behind and only the wealthy nations would be able to afford fossil fuel purchase. This would be the immediate impact of global dependence on fossil fuels.

Fossil fuels are mainly coal, petroleum and natural gas. Since fossil fuels are non-renewable in nature over exploitation may lead to fossil fuels getting exhausted.

Explanation: just took the test

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Answer:

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Explanation:

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(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)

(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)

(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)

(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)

(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)

(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)

From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)

$\text{Probability of getting 11}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\\\Rightarrow \text{Probability of getting 11}=\frac{2}{36}\\\Rightarrow \text{Probability of getting 11}=\frac{1}{18}=0.056$

∴ Probability of getting 11 is<u> 1/18</u>

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