Answer:
t=7.33 s
Explanation:
According to Newton's second law:

because we don't want the box to slide, the acceleration has to be zero.

we know that:

Now having the acceleration, we can use the following formula.

Answer:
The answer is C!!!!!!!
Becuz meters and seconds are derived into m/s²
Explanation:
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Hi there!

Use the equation:

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391


Answer:
E.two angles are vertical angles if, and only if they are not adjacent angles