Answer:
1.429*10^-5 m
Explanation:
From the question, we are given that
Diameter of the cable, d = 3 cm = 0.03 m
Force on the cable, F = 2 kN
Young Modulus, Y = 2*10^11 Pa
Area of the cable = πd²/4 = (3.142 * 0.03²) / 4 = 0.0028 / 4 = 0.0007 m²
The fractional length = Δl/l
Δl/l = F/AY
Δl/l = 2000 / 0.0007 * 2*10^11
Δl/l = 2000 / 1.4*10^8
Δl/l = 1.429*10^-5 m
Therefore, the fractional length is 1.429*10^-5 m long
M = 4kg
F =8N
a..?
F =m.a
8 = 4.a
a = 2m/s^2
The difference in frequency of the two signals is .
The given parameters;
- <em>frequency of the 13 C signal = 201.16 MHz</em>
The energy of the 13 C signal located at 20 ppm is calculated as follows;
The energy of the 13 C signal located at 179 ppm is calculated as follows;
The difference in frequency of the two signals is calculated as follows;
Thus, the difference in frequency of the two signals is .
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I think the answer is A
Hope it helps you
If gravity is the ONLY force acting on an object, then the force of
Earth's gravity produces acceleration of 9.8 meters per second²
downward. That number doesn't change, and it doesn't depend
on the mass or weight of the object.
If there are any other forces acting on the object at the same time,
like air resistance or some other kind of friction for example, then
all bets are off, and we can't say what the object's acceleration will
be in that case.