Answer:
S=720m anf vf=12m/s
Explanation:
acceleration=a=0.1m/s²
time taken=t=2minutes=2×60=120seconds
vi=0m/s
vf=?
distance covered=S=?
by using second equation of motion
S=vit+1/2at²
S=0m/s×120seconds+1/2(0.1m/s²)(120s)²
S=0m/s+1/2×1440m
S=720m
and now we have to find the vf
vf=vi+at
vf=0m/s+(0.1m/s)(120s)
vf=12m/s
i hope it will help you
B. +Q, + W are the correct sign
GPE I am assuming is gravitational potential energy. I'll denote it as U for simplicity.
U = mgy
U = (70kg)(9.81m/s^2)(1m) = 686.7J
U = 686.7J
Hope this helps!
