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dmitriy555 [2]
3 years ago
14

A substance contains only one type of atom. The substance is a/an ____________. A. solution B. element C. mixture D. compound

Physics
2 answers:
masha68 [24]3 years ago
7 0

Answer:

the answer is b

Explanation:

Alex17521 [72]3 years ago
3 0
The answer to this question is:B. Element









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Heat gained minus work fine is equal to what?
Zina [86]

Heat transferred - Work done = Internal Energy

Explanation:

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How do you think overpumping groudwater is related to the formation of sinkholes?
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Ground water keept the ground at a stable level when it is gone the cavern it was in has no support and is at risk of callaps
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Why might the 1990 earthquake and volcanic eruption in Luzon be related?
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3 years ago
Help plzzzzzzz i need thissssssssss
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The final graph

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8 0
2 years ago
The drawing shows an adiabatically isolated cylinder that is divided initially into two identical parts by an adiabatic partitio
Sveta_85 [38]

Answer:

temperature on left side is 1.48 times the temperature on right

Explanation:

GIVEN DATA:

\gamma = 5/3

T1 = 525 K

T2 = 275 K

We know that

P_1 = \frac{nRT_1}{v}

P_2 = \frac{nrT_2}{v}

n and v remain same at both side. so we have

\frac{P_1}{P_2} = \frac{T_1}{T_2} = \frac{525}{275} = \frac{21}{11}

P_1 = \frac{21}{11} P_2 ..............1

let final pressure is P and temp  T_1 {f} and T_2 {f}

P_1^{1-\gamma} T_1^{\gamma} = P^{1 - \gamma}T_1 {f}^{\gamma}

P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

similarly

P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

divide 2 equation by 3rd equation

\frac{21}{11}^{-2/3} \frac{21}{11}^{5/3} = [\frac{T_1 {f}}{T_2 {f}}]^{5/3}

T_1 {f} = 1.48 T_2 {f}

thus, temperature on left side is 1.48 times the temperature on right

6 0
3 years ago
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