Answer:
300.16m/s
Explanation:
An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?
note velocity is the change in displacement to time
to find the magnitude of the initial speed ,
we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root
U=
U=
U=90,100^2
U=300.16m/s
means that it covers 300.16m in 1 seconds
We know that the acceleration due to gravity g is: g =
9.81 m/s^2
So the centripetal acceleration (w) is:
w^2 = 1.5 g / r
w^2 = 1.5 * (9.81 m/s^2) / 5 m
w = 1.716 rad / s
To convert to rad to rev:
w = (1.716 rad / s) * (1 rev / 2π rad) * (60 s/min)
<span>w = 16.4 rev/min </span>
Answer: He came up with this by using theories like the photoelectric effect, the second offered experimental proof of the existence of atoms, and the third introduced the theory of special relativity.
Explanation: He was explaing the realationship between energy and mass.
Me: Hope this helps!!! May I have brainlist!?
Answer:
Bar graph
Explanation:
each day collects data so a bar graph would work.
False. p waves, than s waves