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3 years ago

Argue as to why drivint on icy or snowy roads can be dangerous

1 answer:

6 0

Icy/Snowy roads have less friction than normal roads. This means that the wheels are less likely to stay positioned because of traction, and you will spin out of control

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An engineer wishes to design a curved exit ramp for a toll road in such a way that a car will not have to rely on friction to ro

Dafna11 [192]

To solve this problem we will make a graph that allows us to understand the components acting on the body. In this way we will have the centripetal Force and the Force by gravity generating a total component. If we take both forces and get the trigonometric ratio of the tangent we would have the angle is,

$T_x = nsinA = \frac{mv^2}{r}$

$T_y = ncosA = mg$

Dividing both.

$tan A = \frac{v^2}{rg}$

$tan A = \frac{11.7^2}{50*9.8}$

$A = tan^{-1} (0.279367)$

$A = 15.608\°$

Therefore the angle that should the curve be banked is 15.608°

7 0

3 years ago

On the Moon's surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distanc

dimulka [17.4K]

Answer:

4.88 x 10∧-8 sec

Explanation:

7 0

3 years ago

A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)

salantis [7]

Answer:

The velocity with which the student goes down the bottom of glide is 12.48m/s.

Explanation:

The Non conservative force is defined as a force which do not store energy or get he energy dissipate the energy from the system as the system progress with the motion.

Given are

mass of the student 73 kg

height of water glide 11.8 m

work done as -5.5*10³ J

Have to find speed at which the student goes down the glide.

According to Law of Conservation of energy,

K.E =P.E+Work Done

mv²/2=mgh +W

Rearranging the above eqn for v

v = √2(gh+W/m)

Substituting values,

V = 12.48 m/s.

The velocity with which the student goes down the bottom of glide is 12.48m/s.

3 0

3 years ago

Meter #1 can measure voltage to within 0.1 volts. Meter #2 can measure voltage to within 0.01 volts.

Ann [662]

Meter #2 is more precise.

There's no information here that tells us which meter is more accurate.

4 0

2 years ago

A 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. What is the diameter of t

sladkih [1.3K]

Explanation:

Given that,

Length of gold wire, l = 4 m

Voltage of battery, V = 1.5 V

Current, I = 4 mA

The resistivity of gold, $\rho=2.44\times 10^{-8}\ \Omega-m$

Resistance in terms of resistivity is given by :

$R=\dfrac{\rho l}{A}$

Also, V = IR

So,

$\dfrac{V}{I}=\dfrac{\rho l}{A}$

A is area of wire,

$\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}$ , r is radius, r = d/2 (diameter=d)

$\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m$

Out of four option, near option is (C) 17 μm.

6 0

2 years ago