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KiRa [710]
3 years ago
11

Determine how many moles of Ba(OH)2 are required to completely neutralize 0.117 mole of HC2H3O2.

Chemistry
1 answer:
Naddika [18.5K]3 years ago
6 0
HC₂H₃O₂ (CH₃COOH) - acetic acid
-------------------------------------------------
2CH₃COOH + Ba(OH)₂ ----> (CH₃COO)₂Ba + 2H₂O
2 mol              1 mol

2 mol CH₃COOH -------- 1 mol <span>Ba(OH)₂
0,117 mol </span><span>CH₃COOH ------ X
X = 0,117/2
<u>X = 0,0585 mol  </u></span><span><u>Ba(OH)₂


</u>
</span>
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1. A gas having the following composition is burnt under a boiler with 50% excess air.
jeka94

The composition of the stack gas are :

CH_4= 0.8713

C_3H_8 = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

#SPJ1

8 0
2 years ago
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