The mass of melted gold to release the energy would be 3, 688. 8 Kg
<h3>How to determine the mass</h3>
It is important to note that the formula for energy is
Q = n × HF
Where
n = number of moles
HF = heat of fusion
Let's find number of moles
235.0 = n × 12.550
number of moles = 
= 18. 725 moles
The molar mass of Gold is 197g/ mol
We have that;
Number of moles = mass/ molar mass
Mass = number of moles × molar mass
Substitute the values
Mass = 18. 725 × 197
Mass = 3, 688. 8 Kg
Thus, the mass of melted gold to release the energy would be 3, 688. 8 Kg
Learn more about molar heat of fusion here:
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Answer/Explanation:
They have very high ionization energies so they don't form ions. The noble gases are the least reactive of all the elements but the heavier ones do form some molecules. Helium and neon never form molecules. They have completely filled electron shells with no have-filled orbitals available for making covalent bonds
A molecule with formula AX3E uses SP3 to form its bonds.
Where A is the metal
X is any halogen which is bonded to it.
E is the lone pair
∴ A requires four electron pairs and tetrahedral.
Where tetrahedral symmetry is SP3 hybridized
Answer:
219.78 mL of the stock solution are needed
Explanation:
First, we take a look at the desired Al2(SO4)3 working solution. We are told that the we need 400 mL of an aqueous aluminum sulfate solution 1.0 M. Let's see how many moles of the compound we have in the desired volume:
1000 mL Al2(SO4)3 solution ----- 1 mole of Al2(SO4)3
400 mL Al2(SO4)3 solution ----- x = 0.4 moles of Al2(SO4)3
To reach the desired concentration in the working solution we need 0.4 moles of Al2(SO4)3 in 400 mL, so we calculate the volume of the stock solution needed to prepare the working solution:
1.82 moles Al2(SO4)3/L = 1.82 M → This is the molar concentration of the stock solution.
1.82 moles of Al2(SO4)3 ----- 1000 mL
0.4 moles of Al2(SO4)3 ----- x = 219.78 mL
So, if we take 219.78 mL of the 1.82 M stock solution, we put it in a graduated cylinder and we dilute it to 400 mL, we would obtain a 1.0 M Al2(SO4)3 solution.
Answer: B.The atoms ⚛️ in Damien’s candy are vibrating faster ❣️ Yur Welcome
