Answer:
A is denser than B as it's volume for the same mass is smaller.
Explanation:
Hello.
In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:
![V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL](https://tex.z-dn.net/?f=V_A%3D50.0mL-38.0mL%3D12.0mL%5C%5C%5C%5CV_B%3D60.0mL-38.0mL%3D22.0mL)
Next, we compute the densities as shown below:
![\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\ \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL](https://tex.z-dn.net/?f=%5Crho_A%3D%5Cfrac%7Bm_A%7D%7BV_A%7D%3D%5Cfrac%7B5.00g%7D%7B12.0mL%7D%3D0.42g%2FmL%5C%5C%20%20%5C%5C%5Crho_B%3D%5Cfrac%7Bm_B%7D%7BV_B%7D%3D%5Cfrac%7B5.00g%7D%7B22.0mL%7D%3D0.23g%2FmL)
In such a way, A is denser is B as it's volume for the same mass is smaller.
Best regards.
Answer: I believe it would be using group input to discuss and prepare preliminary designs
Explanation:
Answer:
Heat or Thermal energy, Solar Energy, Chemical energy, electrical energy, mechanical energy
Explanation:
A controlled variable is the one that is kept constant, the manipulated variable is the independent variable in an experiment , it is called manipulated because is the one that can be changed. A responding variable or variables are the dependent variables that change as a result of the changes in the manipulated variable.
Answer:
No
Explanation:
One mole of P₄ react with six moles of I₂ and gives 4 moles of PI₃.
When one gram phosphorus and 6 gram of iodine react they gives 8.234 g
ram of PI₃ .
Given data:
Mass of phosphorus = 1 g
Mass of iodine = 6 g
Mass of PI₃ = ?
Solution:
Chemical equation:
P₄ + 6I₂ → 4PI₃
Number of moles of P₄:
Number of moles = Mass /molar mass
Number of mole = 1 g / 123.9 g/mol
Number of moles = 0.01 mol
Number of moles of I₂:
Number of moles = Mass /molar mass
Number of moles = 6 g / 253.8 g/mol
Number of moles = 0.024 mol
Now we will compare the moles of PI₃ with I₂ and P₄.
I₂ : PI₃
6 : 4
0.024 :
4/6×0.024 = 0.02
P₄ : PI₃
1 : 4
0.01 : 4 × 0.01 = 0.04 mol
The number of moles of PI₃ produced by I₂ are less it will be limiting reactant.
Mass of PI₃ = moles × molar mass
Mass of PI₃ = 0.02 mol × 411.7 g/mol
Mass of PI₃ = 8.234 g