Answer:
308 g
Explanation:
Data given:
mass of Fluorine (F₂) = 225 g
amount of N₂F₄ = ?
Solution:
First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄
Reaction:
2F₂ + N₂ -----------> N₂F₄
Now look at the reaction for mole ratio
2F₂ + N₂ -----------> N₂F₄
2 mole 1 mole
So it is 2:1 mole ratio of Fluorine to N₂F₄
As we Know
molar mass of F₂ = 2(19) = 38 g/mol
molar mass of N₂F₄ = 2(14) + 4(19) =
molar mass of N₂F₄ = 28 + 76 =104 g/mol
Now convert moles to gram
2F₂ + N₂ -----------> N₂F₄
2 mole (38 g/mol) 1 mole (104 g/mol)
76 g 104 g
So,
we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.
Apply unity formula
76 g of F₂ ≅ 104 g of N₂F₄
225 g of F₂ ≅ X of N₂F₄
Do cross multiplication
X of N₂F₄ = 104 g x 225 g / 76 g
X of N₂F₄ = 308 g
So,
308 g N₂F₄ can be produced from 225 g F₂
The elements in a periodic table are arranged in the increasing order of their atomic number.
same number of protons and different number of neutrons are called isotopes
Answer:
23.76g
Explanation:
To solve for the mass of carbon dioxide (CO2), let us first obtain the number of mole of CO2.
From the question, the following were obtained:
V = 8.13L
P = 204kPa = 204000Pa
Recall: 101325Pa = 1atm
204000Pa = 204000/101325 = 2atm
T = 95°C = 95 + 273 = 368K
R = 0.082atm.L/K/mol
n =?
PV = nRT
n = PV /RT
n = 2 x 8.13/ 0.082 x 368
n = 0.54mole
Now let us convert 0.54mole of CO2 to gram. This is illustrated below:
Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol
Number of mole of CO2 = 0.54mole
Mass of CO2 =?
Number of mole = Mass /Molar Mass
Mass = number of mole x molar Mass
Mass of CO2 = 0.54 x 44
Mass of CO2 = 23.76g
