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stellarik [79]
3 years ago
10

A construction worker uses an electrical device to attract fallen nails and sharp objects from a construction site. What is caus

ing the attraction of the metal objects?
An electrical wave oscillating perpendicular to the electrical device.
An electrical charge radiating perpendicular to the wire
A magnetic wave radiating perpendicular to an electrical device
A magnetic wave and electrical current moving in opposite directions
Physics
1 answer:
yan [13]3 years ago
4 0

A magnetic wave and electrical current moving in opposite directions

Explanation:

The attraction of the metallic objects is caused by the magnetic fields produced by the perpendicular vibration of magnetic waves and electric current moving in opposite directions.

  • This vibrations causes the formation of magnetic fields.
  • Such a device is called an electromaget
  • It is a magnet that is produce when electric current produces magnetic fields.
  • In the vicinity of magnetic objects, it will attract it.
  • the construction worker is using an electrmagnet.

learn more:

Electromagnet brainly.com/question/2191993

#learnwithBrainly

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A JFET has a drain current of 5mA. If IDSS = 10mA and VGS ( off )= -6 v. find The Value Of
levacccp [35]

\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{D} = 5mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

\:  \:  \:

<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{5m} }{ \sqrt{10m} } ) \times  { - 6}

\:  \:

  • \underline \color{red} {\tt \large \boxed {\tt V_{GS} = 1.75 ✓}}
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now from above equation

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