It should be 0.25kg because you converter from g to kg and since 1g<1kg so you move the decimal to the left
Answer:
W = - 5.01 10¹⁰ J
Explanation:
Work is defined by the expression
W = ∫ F.dr
Where the blacks indicate vectors, in the case the force is radial and the distance is also radial, whereby the scalar producer is reduced to an ordinary product
W = ∫ F dr
W = G m₁m₂ ∫ 1 /r² dr
W = G m₁ m₂2(-1 / r)
We evaluate between the lower limits r = Re and upper r = ∞
W = G m₁m₂ (-1 / Re + 1 / ∞)
W = - G m₁ m₂ / Re
Let's calculate
W = - 6.67 10⁻¹¹ 800 5.98 10²⁴ / 6.37 10⁶
W = - 5.01 10¹⁰ J
The maximum speed is 10.4 m/s
Explanation:
For a body in uniform circular motion, the centripetal acceleration is given by:
where
v is the linear speed
r is the radius of the circular path
In this problem, we have the following data:
- The maximum centripetal acceleration must be
where 
is the acceleration of gravity. Substituting,
- The radius of the turn is
r = 10 m
Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:
Learn more about centripetal acceleration:
brainly.com/question/2562955
#LearnwithBrainly
Answer:
Explanation:required formula is
W 1=F*S
W1=work done by Sam =?
F=force applied by sam=150N
S=displacement =10m
again
W2=F*S
W2=work done by friction =?
S=displacement =10m
F=friction =25N
W=W1-W2=net work done
please feel free to ask if you have any questions
Answer: 1.2m/s^2
Explanation: the force exerted on the car is 900N upwards
The mass of the car is 750kg
According to Newton's third law acceleration is proportional to force
F = ma
900 = 750a
a = 900/750
a = 1.2m/s^2
