Answer:
Explanation:
NaCl + AgNO3 → NaNO3 + AgCl
5 atoms
no
Answer:
star 3
Explanation:
the color determines the fusion in between
Answer:
9.82% of iron (II) will be sequestered by cyanide
Explanation:
We should first consider that Iron (II) and cyanide react to form the following structure:
[Fe(CN)₆]⁻⁴
Having considered this:
5.60 Lt Fe(II) 3.00x10⁻⁵ M ,this is, we have 5.60x3x10⁻⁵ = 1.68x10⁻⁴ moles of Fe⁺² (in 5.60 Lt)
Then , we have 9 ml NaCN 11.0 mM:
9 ml = 0.009 Lt
11.0 mM (milimolar) = 0.011 M (mol/lt)
So: 0.009x0.011 = 9.9x10⁻⁵ moles of CN⁻ ingested
As we now that the complex structure is formed by 1 Fe⁺² : 6 CN⁻ :
9.9x10⁻⁵ moles of CN⁻ will use 1.65x10⁻⁵ moles of Fe⁺² (this is, this amount of iron (II) will be sequestered
[(1.65x10⁻⁵ sequestred Fe⁺²)/(1.68x10⁻⁴ total available Fe⁺²)x100
% sequestered iron (II) = 9.82%
The principal quantum number (n) describes the size of the orbital. Orbitals for which n = 2 are larger than those for which n = 1, for example. Because they have opposite electrical charges, electrons are attracted to the nucleus of the atom. Energy must therefore be absorbed to excite an electron from an orbital in which the electron is close to the nucleus (n = 1) into an orbital in which it is further from the nucleus (n = 2). The principal quantum number therefore indirectly describes the energy of an orbital.
The angular quantum number (l) describes the shape of the orbital. Orbitals have shapes that are best described as spherical (l = 0), polar (l = 1), or cloverleaf (l = 2). They can even take on more complex shapes as the value of the angular quantum number becomes larger.
