What is the molecular formula of a compound with the empirical SO and molecular weight 96.13?

Chemistry

1 answer:

katovenus [111]3 years ago

5 0

Answer:

Explanation: A compound with the empirical formula SO has a molecular weight of 96.13

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Nitric oxide is formed in automobile exhaust when nitrogen and oxygen in air react at high temperatures.N2(g) + O2(g) 2NO(g)The

yanalaym [24]

Answer : The correct option is, (E) 7.8 atm

Explanation :

The partial pressure of $N_2$ = 8.00 atm

The partial pressure of $O_2$ = 5.00 atm

$K_p$ = 0.0025

The balanced equilibrium reaction is,

$N_2(g)+O_2(g)\rightleftharpoons 2NO(g)$

Initial pressure 8.00 5.00 0

At eqm. (8.00-x) (5.00-x) 2x

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{NO})^2}{(p_{N_2})(p_{O_2})}$

Now put all the values in this expression, we get :

$0.0025=\frac{(2x)^2}{(8.00-x)\times (5.00-x)}$

By solving the terms, we get:

$x=0.15atm$

The equilibrium partial pressure of $N_2$ = (8.00 - x) = (8.00 - 0.15) = 7.8 atm

Therefore, the equilibrium partial pressure of $N_2$ is 7.8 atm.

3 0

3 years ago

A molecular orbital that decreases the electron density between two nuclei is said to be ____.

nikklg [1K]

A molecular orbital that decreases the electron density between two nuclei is said to be antibonding.

The bonding orbital, which would be more stable and encourages the bonding of the two H atoms into $H_{2}$ , is the orbital that is located in a less energetic state than just the electron shells of the separate atoms. The antibonding orbital, which has higher energy but is less stable, resists bonding when it is occupied.

An asterisk (sigma*) is placed next to the corresponding kind of molecular orbital to indicate an antibonding orbital. The antibonding orbital known as * would be connected to sigma orbitals, as well as antibonding pi orbitals are known as $\pi$ * orbitals.