Answer:
<u>Distance</u><u> </u><u>between</u><u> </u><u>them</u><u> </u><u>is</u><u> </u><u>4</u><u>,</u><u>2</u><u>0</u><u>0</u><u> </u><u>meters</u><u>.</u>
Explanation:
Consinder car A:
![{ \bf{distance = speed \times time }}](https://tex.z-dn.net/?f=%7B%20%5Cbf%7Bdistance%20%3D%20%20speed%20%5Ctimes%20time%20%7D%7D)
substitute:
![distance = 20 \times (2 \times 60) \\ = 2400 \: m](https://tex.z-dn.net/?f=distance%20%3D%2020%20%5Ctimes%20%282%20%5Ctimes%2060%29%20%5C%5C%20%20%3D%202400%20%5C%3A%20m)
Consider car B:
![distance = 15 \times (2 \times 60) \\ = 1800 \: m](https://tex.z-dn.net/?f=distance%20%3D%2015%20%5Ctimes%20%282%20%5Ctimes%2060%29%20%5C%5C%20%20%3D%201800%20%5C%3A%20m)
since these cars move in opposite directions, distance between them is their summation:
![distance \: between = { \sum(distance \: of \: each \: car)} \\ = 2400 + 1800 \\ = 4200 \: m](https://tex.z-dn.net/?f=distance%20%5C%3A%20between%20%3D%20%7B%20%5Csum%28distance%20%5C%3A%20of%20%5C%3A%20each%20%5C%3A%20car%29%7D%20%5C%5C%20%20%3D%202400%20%2B%201800%20%5C%5C%20%20%3D%204200%20%5C%3A%20m)
Depends on what type of mirror that is. I am going to assume this is a plain mirror (from the phrase), which means the height and width of the object and image is exactly the same.
Newton's third law of motion states that for every action there is an equal and opposite reaction. The balloon travels in the opposite direction as the air escaping from it. So when gas is released from the balloon it pushes against the outside air and the outside air pushes back. As a result of this the rocket is propelled forward by the opposing force. This opposing force is thrust.
Hope this helps!
Can u plz mark me as brainliest? I really need it!