Answer:
Explanation:
Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.
Answer:
the answer is C
Explanation:
gravity forces down not up or sideways.
Answer:
a).11.546J
b).2.957kW
Explanation:
Using Inertia and tangential velocity
a).
![w=2250*2\pi *\frac{1}{60}\\ w=235.61](https://tex.z-dn.net/?f=w%3D2250%2A2%5Cpi%20%2A%5Cfrac%7B1%7D%7B60%7D%5C%5C%20w%3D235.61)
![I=\frac{1}{2}*m*((\frac{d_{i} }{2})^{2} +(\frac{d_{e} }{2})^{2})\\m=100g *\frac{ikg}{1000g}=0.1kg\\ d_{i}=3cm*\frac{1m}{100cm}=0.03m \\ d_{e}=18cm*\frac{1m}{100cm}=0.18m\\I=\frac{1}{2}*0.1kg*((\frac{0.03m}{2})^{2} +(\frac{0.18m}{2})^{2})\\I=0.41625x10^{-3}kg*m^{2}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B2%7D%2Am%2A%28%28%5Cfrac%7Bd_%7Bi%7D%20%7D%7B2%7D%29%5E%7B2%7D%20%2B%28%5Cfrac%7Bd_%7Be%7D%20%7D%7B2%7D%29%5E%7B2%7D%29%5C%5Cm%3D100g%20%2A%5Cfrac%7Bikg%7D%7B1000g%7D%3D0.1kg%5C%5C%20d_%7Bi%7D%3D3cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.03m%20%5C%5C%20d_%7Be%7D%3D18cm%2A%5Cfrac%7B1m%7D%7B100cm%7D%3D0.18m%5C%5CI%3D%5Cfrac%7B1%7D%7B2%7D%2A0.1kg%2A%28%28%5Cfrac%7B0.03m%7D%7B2%7D%29%5E%7B2%7D%20%2B%28%5Cfrac%7B0.18m%7D%7B2%7D%29%5E%7B2%7D%29%5C%5CI%3D0.41625x10%5E%7B-3%7Dkg%2Am%5E%7B2%7D)
Now using Inertia an w
![E=\frac{1}{2}*I*(w)^{2} \\ E=\frac{1}{2}*0.416x10^{-3}*(235.61)^{2} \\E=11.54J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B2%7D%2AI%2A%28w%29%5E%7B2%7D%20%5C%5C%20E%3D%5Cfrac%7B1%7D%7B2%7D%2A0.416x10%5E%7B-3%7D%2A%28235.61%29%5E%7B2%7D%20%5C%5CE%3D11.54J)
average power=![\frac{11.4J}{0.230s}=50.2 W](https://tex.z-dn.net/?f=%5Cfrac%7B11.4J%7D%7B0.230s%7D%3D50.2%20W)
b).
power=t*w
P=![11.5465*0.25*235.61](https://tex.z-dn.net/?f=11.5465%2A0.25%2A235.61)
P=2.957 kW
I don't really know the answer but maybe north pole and south pole?
The lens changes the focal distance of the eye so that you can focus on images/objects.