All categories

3 years ago

Select the property of equality used to arrive aSelect the property of equality used to arrive at the conclusion.

Mathematics

2 answers:

vovikov84 [41]3 years ago

7 0

would it be b

I really don't know thou

Luda [366]3 years ago

4 0

the answer would be D., x+8=10 you are going to subtract 8 from both sides to get x=2

You might be interested in

Please help math part2

Keith_Richards [23]

How I got my answer before was substitution!

5 0

2 years ago

Match the equation with the graph -0.4x-0.8y=0.10

laiz [17]

Can't see the graph, but it should look something like this:

7 0

2 years ago

Evaluate (-7)2. p l e a s e a n s w e r q u i c k\

devlian [24]

Answer:

(-7)2 = -14

Step-by-step explanation:

The parenthesis basically mean "multiply". So, this is a simple equation meaning -7 x 2. And remember, anytime we multiply a positive by a negative, you get a negative. So, simply multiply 7 x 2 = 14 and add a negative sign to make the solution true. So, -7 x 2 or (-7)2 = -14

Hope this helps! If you have any additional questions, please don't hesitate to ask me or your teacher to be sure you master the subject. Also thank you for the generous points!! Stay safe and please mark brainliest!!

7 0

3 years ago

Read 2 more answers

A jar contains a mixture of 10 black balls, 8 red balls, and 2 white balls all the same size. What is the probability of drawing

gayaneshka [121]

Red 8/20 white 2/20 both 50% or 10/20

7 0

3 years ago

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

7 0

2 years ago