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lara31 [8.8K]
3 years ago
13

The diagram shows a ball resting at the top of a hill. A ball is at the top of a slope at point X. The bottom of the slope is po

int Y. Which statement best describes the energy in this system? The potential energy in the system is greatest at X. The kinetic energy in the system is greatest at X. Total energy in the system decreases as the ball moves from X to Y. Total energy in the system increases as the ball moves from X to Y.
Chemistry
2 answers:
vlada-n [284]3 years ago
5 0

Answer:

the potential energy in the system is greatest at X

Explanation:

lidiya [134]3 years ago
4 0

Answer:

A

Explanation:

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If you assume this reaction is driven to completion because of the large excess of one ion, what is the concentration of [Fe(SCN
viktelen [127]

Answer : The concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

Explanation :

When we assume this reaction is driven to completion because of the large excess of one ion then we are assuming limiting reagent is SCN^- and Fe^{3+} is excess reagent.

First we have to calculate the moles of KSCN.

\text{Moles of }KSCN=\text{Concentration of }KSCN\times \text{Volume of solution}

\text{Moles of }KSCN=0.00180M\times 0.006L=1.08\times 10^{-5}mol

Moles of KSCN = Moles of K^+ = Moles of SCN^- = 1.08\times 10^{-5}mol

Now we have to calculate the concentration of [Fe(SCN)]^{2+}

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{\text{Moles of }[Fe(SCN)]^{2+}}{\text{Volume of solution}}

Total volume of solution = (6.00 + 5.00 + 14.00) = 25.00 mL = 0.025 L

\text{Concentration of }[Fe(SCN)]^{2+}=\frac{1.08\times 10^{-5}mol}{0.025L}=4.32\times 10^{-4}M

Thus, the concentration of [Fe(SCN)]^{2+} is, 4.32\times 10^{-4}M

7 0
2 years ago
What is the theoretical yield of aluminum oxide if 1.40 mol of aluminum metal is exposed to 1.35 mol of oxygen?
jasenka [17]

Answer:

71.372 g or 0.7 moles

Explanation:

We are given;

  • Moles of Aluminium is 1.40 mol
  • Moles of Oxygen 1.35 mol

We are required to determine the theoretical yield of Aluminium oxide

The equation for the reaction between Aluminium and Oxygen is given by;

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.

Therefore;

1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen

1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium

Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.

4 moles of aluminium reacts to generate 2 moles aluminium oxide.

Therefore;

Mole ratio Al : Al₂O₃ is 4 : 2

Thus;

Moles of Al₂O₃ = Moles of Al × 0.5

                         = 1.4 moles × 0.5

                         = 0.7 moles

But; 1 mole of Al₂O₃ = 101.96 g/mol

Thus;

Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol

                                            = 71.372 g

3 0
3 years ago
A student finds that the water's temperature went from 18oC to 38oC. Calculate how many calories are in the peanut.
Norma-Jean [14]

Answer:

567 calories.

Explanation:

There 567 calories in 100 grams of peanut. In 100 grams of peanut, 49 gram is the fat, 26 grams of protein, 16 grams of carbohydrates, Sodium is 18 mg, Potassium is 705 mg. Calcium is present in peanut about 9%, Iron is 25% , Vitamin B-6 is 15%  and Magnesium is 42% of their total weight. Oil content is high in the Peanut so this is the reason for high calories in peanut. It is a good source of proteins and potassium.

4 0
3 years ago
. Which of the following animals is sessile?
storchak [24]

Answer:

A) Jellyfish

Explanation:

has a sessile larval stage as a polyp, leading to a motile stage as they reach maturity. Conversely, organisms such as barnacles have a motile, pelagic larval stage and become sessile in their adult life

4 0
2 years ago
Read 2 more answers
What is the mass of 2.50 moles of potassium chlorate in grams
Sedaia [141]

Answer: 306 grams are there in 2.50 moles of potassium chlorate

Explanation

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

given mass of potassium chlorate = ?

Molar mass of potassium chlorate = 122.55 g/mol

Putting in the values we get:

2.50=\frac{xg}{122.55g/mol}

x=2.50mol\times 122.55g/mol=306g

306 grams are there in 2.50 moles of potassium chlorate

3 0
3 years ago
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