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Solnce55 [7]
3 years ago
6

Which of the following is not a technological way of improving air pollution

Chemistry
2 answers:
anyanavicka [17]3 years ago
4 0
Composting is not a technological way of improving air quality.

I hope this helps!
nydimaria [60]3 years ago
3 0

Answer:

C. composting

Explanation:

i took the test

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How do substances and mixtures diifer
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Answer:

hello hope this helps :)

a pure substance consists only of one element or one compound. a mixture consists of two or more different substances, not chemically joined together.

Explanation:

5 0
3 years ago
What is a substance?
shusha [124]

I think the answer is C. An element or compound that cannot be physically separated. Sorry if im wrong.

7 0
4 years ago
PLEASE HELP ASAP ESSAY WORTH 15 POINTS! ONLY GENIUS!
Sliva [168]

Answer:

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products.

Explanation:

5 0
3 years ago
6. What is the number of moles of KF in a 29 gram sample?
stich3 [128]
Not sure but it might be A or B
3 0
3 years ago
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
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