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s344n2d4d5 [400]
2 years ago
11

How long does it take an object to travel 50m at a rate of 8 m/s?

Chemistry
1 answer:
Harman [31]2 years ago
7 0

Answer:

6.25s

Explanation:

time = distance / speed

time = 50 / 8

time = 6.25s

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The table below shows the number of sub-atomic particles in an atom of magnesium.
Fittoniya [83]

Answer:

24

Explanation:

7 0
3 years ago
What is the empirical formula of a compound that contains 25.92 percent nitrogen and 74.07 percent oxygen?
pychu [463]

<span><span>N2</span><span>O5</span></span>

Explanation! 

When given %, assume you have 100 g of the substance. Find moles, divide by lowest count. In this case you'll end up with

<span><span>25.92 g N<span>14.01 g N/mol N</span></span>=1.850 mol N</span>

<span><span>74.07 g O<span>16.00 g O/mol O</span></span>=4.629 mol O</span>

The ratio between these is <span>2.502 mol O/mol N</span>, which corresponds closely with <span><span>N2</span><span>O5</span></span>.

4 0
3 years ago
Read 2 more answers
Which is the best example of translate translational motion
RoseWind [281]

The correct answer would be A) A soccer ball passed between two players because the ball is in motion.

6 0
3 years ago
When PCl5 solidifies it forms PCl4+ cations and PCl6– anions. According to valence bond theory,
rewona [7]

Hey there!

No of hybrid orbitals , H = ( V +S - C + A ) / 2

Where H = no . of hybrid orbitals

V = Valence of the central atom = 5

S = No . of single valency atoms = 4

C = No . of cations = 1

A = No . of anions = 0

For PCl4 +

Plug the values we get H = ( 5+4-1+0) / 2

H =  4 ---> sp3 hybridization

sp3 hybrid orbitals are used by phosphorous in the PCl4+ cations

Answer C

Hope that helps!

3 0
3 years ago
Need help with 22 and 24<br>​
choli [55]

Answer:

22:

Formular:

atomic \: mass =  \frac{ \sum(isotopic \: mass \times \%abundance)}{100}  \\

substitute:

atomic \: mass =  \frac{(23.985 \times 78.70) + (24.986 \times 10.13) + (25.983 \times 11.17)}{100}  \\  \\  =  \frac{(1887.620) + (253.108) + (290.230)}{100}  \\  \\  =  \frac{2430.958}{100}  \\  \\ { \boxed{ \boxed{average \: atomic \: mass = 24.3 \: amu}}}

23:

<em>Same</em><em> </em><em>element</em><em> </em><em>is</em><em> </em><em>represented</em><em> </em><em>by</em><em> </em><em>same</em><em> </em><em>number</em><em> </em><em>of</em><em> </em><em>protons</em><em>.</em><em> </em>

Answer:

6 protons. 6 protons

7 neutrons. 8 neutrons

6 electrons. 6 electrons

Note: <u>Atoms</u><u> </u><u>with</u><u> </u><u>same</u><u> </u><u>proton</u><u> </u><u>number</u><u> </u><u>but</u><u> </u><u>different</u><u> </u><u>mass</u><u> </u><u>number</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>isotopes</u>

5 0
3 years ago
Read 2 more answers
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