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Gnesinka [82]
3 years ago
7

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:

Chemistry
2 answers:
fredd [130]3 years ago
8 0
The answer to your question is D. 24g
egoroff_w [7]3 years ago
6 0

The grams  of  oxygen that are required  to produce 1  mole  of H₂O  is 16 g ( answer  B)

<u><em> calculation</em></u>

2 CH₄  + 2NH₃ +3 O₂ → 2HCN  + 6H₂O

step 1: use the mole ratio to find moles of O₂

from equation above the  mole ratio  of O₂: H₂O  is 3:6 therefore the moles of O₂  = 1 mole x3/6 =0.5 moles

step  2: find   mass of O₂

mass= moles x molar mass

from periodic table the molar mass  of O₂ = 16 x2= 32 g/mol

mass O₂ = 0.5 moles x 32 g/mol = 16 g (answer B)

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Suppose that a sample of gas occupies 187 mL
drek231 [11]

Answer:

V2 = 90.7 mL

Explanation:

pressure and volume are inversely proportional, if the pressure is increased, the volume will decrease. In an isothermal process:

p1V1 = p2V2

V2 = p1V1/p2 = (277 torr×187 mL)/571 torr

V2 = 90.7 mL

7 0
3 years ago
The properties of two elements are listed below. Which prediction is supported by the information in the table?
ANEK [815]
K will give up an electron more easily than Br.
3 0
3 years ago
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The reaction of hydrogen(g) with fluorine(g) to form hydrogen fluoride(g) proceeds as follows: H2(g) + F2(g) 2 HF(g) When 0.647
Nata [24]

<u>Answer:</u> The value of \Delta H for the reaction will be -537 kJ

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of hydrogen gas = 0.647 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen gas}=\frac{0.647g}{2g/mol}=0.324mol

We are given:

Energy released for 0.324 moles of hydrogen reacted is 174 kJ

For the given chemical reaction:

H_2(g)+F_2(g)\rightarrow 2HF(g)

By Stoichiometry of the reaction:

When 0.324 moles of hydrogen gas is reacted, the energy evolved is 174 kJ

So, when 1 mole of hydrogen gas will react, the energy evolved will be = \frac{174kJ}{0.324mol}\times 1mol=537kJ

<u>Sign convention of heat:</u>

When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.

Hence, the value of \Delta H for the reaction will be -537 kJ

6 0
3 years ago
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
4 years ago
The purpose of a machine is to decrease the work needed. TRUE/FALSE
aniked [119]

Answer:

False.

Explanation:

A machine does not decrease the work needed. It simply makes the work easier or changes how the work is done.

8 0
3 years ago
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