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Gnesinka [82]
3 years ago
7

Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:

Chemistry
2 answers:
fredd [130]3 years ago
8 0
The answer to your question is D. 24g
egoroff_w [7]3 years ago
6 0

The grams  of  oxygen that are required  to produce 1  mole  of H₂O  is 16 g ( answer  B)

<u><em> calculation</em></u>

2 CH₄  + 2NH₃ +3 O₂ → 2HCN  + 6H₂O

step 1: use the mole ratio to find moles of O₂

from equation above the  mole ratio  of O₂: H₂O  is 3:6 therefore the moles of O₂  = 1 mole x3/6 =0.5 moles

step  2: find   mass of O₂

mass= moles x molar mass

from periodic table the molar mass  of O₂ = 16 x2= 32 g/mol

mass O₂ = 0.5 moles x 32 g/mol = 16 g (answer B)

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The contribution to the nature of light-

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Thomas Young proposed the most important double-slit experiment which shows that light acts like a wave and shows the pattern of interferences.

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3 years ago
If a system has a reaction quotient of 2.13 ✕ 10−15 at 100°C, what will happen to the concentrations of COBr2, CO, and Br2 as th
qaws [65]

This is an incomplete question, here is a complete question.

Consider the following equilibrium at 100°C.

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

K_c=4.74\times 10^4

Concentration at equilibrium:

[COBr_2]=1.58\times 10^{-6}M

[Co]=2.78\times 10^{-3}M

[Br_2]=2.51\times 10^{-5}M

If a system has a reaction quotient of 2.13 × 10⁻¹⁵ at 100°c, what will happen to the concentrations of COBr₂, Co and Br₂ as the reaction proceeds to equilibrium?

Answer : The concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

COBr_2(g)\rightleftharpoons CO(g)+Br_2(g)

The expression for reaction quotient will be :

Q=\frac{[CO][Br_2]}{[COBr_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(2.78\times 10^{-3})\times (2.51\times 10^{-5})}{(1.58\times 10^{-6})}=4.42\times 10^{-2}

The given equilibrium constant value is, K_c=4.74\times 10^4

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q that means product < reactant. So, the reaction is product favored that means reaction must shift to the product (right) to be in equilibrium.

Hence, the concentrations of Co and Br₂ decreases and the concentrations of COBr₂ increases.

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3 years ago
100 POINTS!!! :0! What two things do all chemical reactions have in common (tick 2)? 1. They create new substances- the substanc
dusya [7]

Answer:

1 and 4

Explanation:

7 0
3 years ago
Read 2 more answers
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