Answer:
The neutral atoms of the element have an oxidation number of 0. When the atoms loose their three valence electrons to form ions they then have an oxidation number of +3
Explanation:
Ambersnyder, Your answer would be A).
Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.
Explanation:
When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:
Mn2+(aq) + 2e-⟶ Mn(s) E1 = −1.185
Ba2+(aq) + 2e-⟶ Ba(s) E2 = −2.912
By considering the above two reactions, the standard electrode potential can be calculated.
The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts
What is standard electrode potential?
Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.
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No acids have a ph of less than 7 our rain is around a six. dilated water is a 7 and any thing above a 7 is a base
Answer: the molarity of the solution in volumetric flask "B' is 0.0100 M
Explanation:
Given that;
the Molarity of stock solution M₁ = 1.25M
The molarity os solution in volumetric flask A (M₂) = M₂
Volume of stock solution pipet out (V₁) = 5.00mL
Volume of solution in volumetric flask A V₂ = 25.00mL
using the dilution formula
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
WE SUBSTITUTE
M₂ = ( 1.25 × 5.00 ) / 25.00 mL
M₂ = 0.25 M
Now volume of solution pipet out from volumetric flask A V₂ = 2.00 mL
Molarity of solution in volumetric flask B (M₃) = M₃
Volume of solution in volumetric flask B V₃ = 50.00m L
Using dilution formula again
M₂V₂ = M₃V₃
M₃ = M₂V₂ / V₃
WE SUBSTITUTE
M₃ = ( 0.25 × 2.0) / 50.0
M₃ = 0.0100 M
Therefore the molarity of the solution in volumetric flask "B' is 0.0100 M
