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zzz [600]
4 years ago
15

The period of an ocean wave is 5 seconds. What is the wave's frequency?

Physics
1 answer:
Oksana_A [137]4 years ago
7 0

Answer:

f=1/5= 0.2 Hz

..,...........

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Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 15 cm apart. The sound
sineoko [7]

Answer:

100 cm

Explanation:

It is given that there are two loudspeakers that produces $\text{sound waves }$ along x-axis.

The maximum intensity of the sound is $\text{when the speakers are}$ at a distance of = 15 cm apart.

The sound intensity becomes zero when the separation between the speakers are increased and becomes 65 cm.

Therefore, the sound waves are in the phase, $\Delta x_1=15 \ cm$

The sound waves are out of phase when $\Delta x_2=65 \ cm$

Therefore,

$\Delta x_2 - \Delta x_1 = \frac{\lambda}{2}$

$\lambda= 2(\Delta x_2 - \Delta x_1)$

  = 2 (65 - 15)

  = 2 x 50

  = 100 cm

Hence the wavelength of the sound is 100 cm.

5 0
3 years ago
An inexperienced catcher catches a 126 km/h fastball of mass 160 g within 1.36 ms, whereas an experienced catcher slightly retra
Firdavs [7]

Answer:

4117.65 N

Explanation:

Speed of ball, u = 126 km/h = 35 m/s

Mass of ball, m = 160 g = 0.16 kg

Time interval, t = 1.36 ms = 0.00136 s

We can calculate the force as a measure of the momentum of the ball:

F = P/t

Momentum, P, is given as:

P = mv

Therefore:

F = (mv) / t

F = (0.16 * 35) / (0.00136)

F = 4117.65 N

The force imparted to the two glove d hands of the inexperienced catcher is 4117.65 N.

6 0
3 years ago
. Calculate the time take and the distance covered by a train moving with a velocity of 15 m/s to accelerate uniformly at the ra
Oksi-84 [34.3K]

Answer:

a = (V2 - V1) / t     for uniform acceleration

t = (20 - 15/ m/s / 2 m/s^2 = 2.5 s

S = V1 t + 1/2 a t^2     distance covered

S = 15 * 2.5 + 2 / 2 * 2.5^2 = 37.5 +  2.5*2

S = 37.5 + 6.25 = 43.75 m

6 0
2 years ago
A 87 kgkg skydiver can be modeled as a rectangular "box" with dimensions 18 cmcm ×× 47 cmcm ×× 180 cmcm . If he falls feet first
garik1379 [7]

Answer:

Therefore the terminal velocity = 1.45 m/s

Explanation:

Terminal velocity: Terminal velocity is the highest velocity of an object when it falls from rest trough a media.

V_t=\sqrt{\frac{2w}{c_d\rho A}}

V_t= terminal velocity

w = weight of the object = mg

c_d = drag coefficient=0.80

A= frontal area

\rho = media density = 1.2 kg/m³

m = mass = 8 kg

g= acceleration due to gravity = 9.8 m/s²

Front area = length× breadth

                 = (18×47)cm²

                 =846 cm²

Therefore the terminal velocity

v_t= \sqrt{\frac{2\times 87\times 9.8}{0.80\times 846 \times 1.2}

    =1.45 m/s

Therefore the terminal velocity = 1.45 m/s

8 0
3 years ago
Which of the following statement is not true about machines?
viva [34]
The answer to this question is D or the last one 

4 0
3 years ago
Read 2 more answers
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