Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
<u>Cable should be pre-cut and hung suspended for 48 hours to develop its most natural set and lay prior to installation.</u>
<u>Cable should be installed with, not against, its natural set. ... </u>
<u>Strain relief on either end will reduce conductor breakage at the flex points.</u>
Answer:
P.E.T
Explanation:
Stud is a short form of stud wall which are typically vertical framing members in a wall of a building. Wall studs are available in standard lengths but since the height of ceiling vary, sometimes one has to cut the stud walls on site to fit. Therefore, there are pre-cut studs which are more efficient in implementation. These are usually referred as Precision-End Trimmed studs, (P.E.T). Therefore, stud walls which are cut to exact length at the mill for modern construction are designated by letters P.E.T
Answer:
The right solution is "28.45%".
Explanation:
The given values are:



and,





At 45,
⇒ 

At
,

or,

then,
⇒ 

hence,
The isentropic efficiency of turbine will be:
⇒ 

(%)
The thermal efficiency of cycle will be:
⇒ 

(%)
Solution :
Finding the cohesion of the soil(c) using the relation:

Here,
is the unconfined compression strength of the soil;

= 400 psf
∴ The cohesion value is greater than 0
So the use of the angle of internal friction is 0
Referring to the table relation between bearing capacity factors and angle of internal friction.
For the angle of inter friction 



Therefore,

= 2386 psf
∴ Allowable bearing capacity 

∴ 

∴ B = 0.2 ft
Therefore, the dimension of the square footing is 0.2 ft x 0.2 ft
