Answer:
hello your question lacks the required question attached below is the missing diagram
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
Explanation:
Forces in GJ = -4.4444 i.e. 4.4444 tons
Forces in IG = 15.382 tons ( T )
attached below is the detailed solution
Answer:
a) specific impulse = 203 s
(b) mass flow rate = 2511 kg/s
(c) throat diameter = 0.774 m
(d) exit diameter = 1.95 m
(e) thrust = 5.3*10^6 N/m^2
(f) thrust at sea level = 15.6*10^6 N
(g) thrust with hydrogen = 5*10^6 N
(h) thrust with stagnation = 5*10^6 N
Explanation:
See the attached file for explanation.
Where you from?England has so many school subjects,but my country hasn’t got it.Do you like it
Answer:
Attached below are the sketches
answer :
c) G(s) = 100 / ( s + 100 )
d) y'(t) + 100Y(s) = 100 X(s)
e) g(t) = e^-100t u(t)
Explanation:
a) Sketch the bode plot
The filter here is a low pass filter
b) Sketch the s-plane
attached below. pole ( s ) is at 100
c) write the transfer function of the filter
Transfer function ; G(s) = 100 / ( s + 100 )
d) write the differential equation
Y(s) / X(s) = 100 / s + 100
Y(s) [ s + 100 ] = 100 X(s)
= sY(s) + 100Y = 100 X(s)
∴ differential equation = y'(t) + 100Y(s) = 100 X(s)
e) write out the unforced transient response
g(t) = e^-100t u(t)
f) write out the frequency response
attached below
Answer:
what are the options available?