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3 years ago

How many grams of KNO3 will dissolve in 100 g H2O at 50°C?

Chemistry

1 answer:

Cloud [144]3 years ago

7 0

3-89fg I think I’m trying to figure it out

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there are 125 lima beans 56 garbanzo beans 39 kidney beans and 144 green peas in a container. find the percent by number of gree

Sauron [17]

39.6% of the beans are green beans

5 0

3 years ago

Question 15 Measurements show that the energy of a mixture of gaseous reactants decreases by during a certain chemical reaction,

Tresset [83]

Answer:

20+56+760383848483838393949494994

3 0

3 years ago

A 10-liter container has 2 moles of oxygen at a pressure of 92 kpa. The effective speed (rms) of the oxygen molecules in the gas

bezimeni [28]

The effective speed (rms) of the oxygen gas is 293.68 m/s.

<h3></h3><h3>What is Root-mean-square velocity?</h3>

Root mean square velocity is the square root of the mean of squares of the velocity of individual gas molecules

$v_{rms}=\sqrt[]{\frac{3RT}{M} }$

<em>where </em>R = universal gas constant

M = molar mass of the gas in kg/mol

T = temperature in Kelvin

According to the ideal gas law,

PV = nRT

RT = $\frac{PV}{n}$

Substitute in the rms velocity formula,

$v_{rms} = \sqrt[]{\frac{3PV}{nM} }$

P = 92 kPa, V = 10 L, n = 2 moles and M = 32 x 10⁻³ kg/mol

$v_{rms} = \sqrt[]{\frac{3\times92\times10}{2\times32\times10^-^3} }$

=293.68 m/s

Thus, the effective speed (rms) of O₂ gas is 293.68 m/s.

Learn more about Root-mean-square velocity:

brainly.com/question/15995507

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4 0

1 year ago

Joebert had a rectangular cup and filled it with water. He measured the water's mass and volume. Then he got a density of 1.25g/

ANTONII [103]

Answer:

Percent error = 25%

Explanation:

Given data:

Measured density of water = 1.25 g/mL

Accepted density value of water = 1 g/mL

Percent error = ?

Solution:

Formula:

Percent error = (measured value - accepted value / accepted value) × 100

Now we will put the values in formula:

Percent error = (1.25 g/mL - 1 g/mL /1 g/mL )× 100

Percent error = (0.25 g/mL /1 g/mL )× 100

Percent error = 0.25 × 100

Percent error = 25%

5 0

3 years ago

SOLVE The density of a gas is 0.68 g/mL. What amount of space would 23.8 g of this gas occupy?

Contact [7]

Answer:

<h2>The answer is 35 mL</h2>

Explanation:

Density of a substance can be found by using the formula

$Density(\rho) = \frac{mass}{volume}$

From the question we are finding the amount of space the gas will occupy that's the volume of the gas

Making volume the subject we have

$volume = \frac{mass}{Density}$

From the question

mass = 23.8 g/mL

Density = 0.68 g/mL

Substitute the values into the above formula and solve

That's

$volume = \frac{23.8}{0.68}$

We have the final answer as

Hope this helps you

6 0

3 years ago