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Complete question:
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?
Answer:
The electric field strength at the mid-point between the two rings is zero.
Explanation:
Given;
diameter of each ring, d = 10 cm = 0.1 m
distance between the rings, r = 21.0 cm = 0.21 m
charge of each ring, q = 40 nC = 40 x 10⁻⁹ C
let the midpoint between the two rings = x
The electric field strength at the midpoint between the two rings is given as;

Therefore, the electric field strength at the mid-point between the two rings is zero.
Answer:
Mike can travel 80 Km in 4 hours
Answer:
The value is 
Explanation:
From the question we are told that
The value of charge on each three point charge is

The length of the sides of the equilateral triangle is 
Generally the total potential energy is mathematically represented as
![U = k * [ \frac{q_1 * q_2}{r} + \frac{q_2 * q_3}{r} + \frac{q_3 * q_1}{r} ]](https://tex.z-dn.net/?f=U%20%20%3D%20k%20%2A%20%20%5B%20%5Cfrac%7Bq_1%20%2A%20%20q_2%7D%7Br%7D%20%20%2B%20%20%5Cfrac%7Bq_2%20%2A%20%20q_3%7D%7Br%7D%20%20%20%2B%20%5Cfrac%7Bq_3%20%2A%20%20q_1%7D%7Br%7D%20%5D)
=>
Here k is coulomb constant with value 
=>
The 2 means there are two phosphate ions in a molecule of magnesium phosphate.