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AVprozaik [17]
3 years ago
12

Makenna surveyed 48 of her female classmates to determine the number of stores each one visited before purchasing a dress for th

e spring dance. She wants to represent her results in a box plot.
How many values in her data set will be above the third quartile for her box plot?
Physics
2 answers:
Maslowich3 years ago
6 0

48/4 = 12

the answer is 12


Aleonysh [2.5K]3 years ago
5 0

Answer: 12 values

Explanation:

In statistics, a Boxplot is a graph that is a good indicator of how the values in the data are spread out. It is useful when we need to compare distributions between many groups or datasets. It is composed of Outliers, which display low minimums and high maximums. Also, it shows The Interquartile Range by a square composed of Q1 (quartile 1), Q2 (quartile 2) and Median.

Quartiles are values that divide data into quarters, where Q1 represents the lowest 25% of numbers, Q2 represents the next lowest 25% of numbers, Q3 represents the second-highest 25% of numbers above the median and finally, Q4 represents the highest 25% of numbers.

In this case,  her data set is composed of 48 values obtained by the survey Makenna did in her class. Then, numbers above the third quartile for her box plot will be Q4 values, hence, the highest 25% of numbers are:

                                              48 x 25% = 12

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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre
Evgen [1.6K]

Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20  \ \Omega

Answer:

The current is   I =  0.0007 41 \ A

Explanation:

From the question we are told that

   The  area is  A = 8.00 \ cm^2  = 8.0 *10^{-4} \  m^2

   The initial magnetic field at t_o = 0 \ seconds  is B_i = 0.500 \ T

   The magnetic field at t_1 = 0.99 \ seconds is  B_f  = 1.60 \ T

     The resistance is  R = 1.20  \ \Omega

Generally the induced emf is mathematically represented as

      \epsilon  =  A * \frac{B_f - B_i }{ t_f - t_o }

=>   \epsilon  =  8.0 *10^{-4} * \frac{1.60  - 0.500 }{ 0.99- 0  }

=>   \epsilon  = 0.000889 \ V

Generally the current induced is mathematically represented as

     I = \frac{\epsilon}{R }

=>  I = \frac{0.000889}{ 1.20 }  

=>  I =  0.0007 41 \ A  

6 0
2 years ago
Help please i will mark brainlist!!
Dmitrij [34]
The answer is A.


p=m/v
p= 240/60
p= 4 g/cm^3
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