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AVprozaik [17]
3 years ago
12

Makenna surveyed 48 of her female classmates to determine the number of stores each one visited before purchasing a dress for th

e spring dance. She wants to represent her results in a box plot.
How many values in her data set will be above the third quartile for her box plot?
Physics
2 answers:
Maslowich3 years ago
6 0

48/4 = 12

the answer is 12


Aleonysh [2.5K]3 years ago
5 0

Answer: 12 values

Explanation:

In statistics, a Boxplot is a graph that is a good indicator of how the values in the data are spread out. It is useful when we need to compare distributions between many groups or datasets. It is composed of Outliers, which display low minimums and high maximums. Also, it shows The Interquartile Range by a square composed of Q1 (quartile 1), Q2 (quartile 2) and Median.

Quartiles are values that divide data into quarters, where Q1 represents the lowest 25% of numbers, Q2 represents the next lowest 25% of numbers, Q3 represents the second-highest 25% of numbers above the median and finally, Q4 represents the highest 25% of numbers.

In this case,  her data set is composed of 48 values obtained by the survey Makenna did in her class. Then, numbers above the third quartile for her box plot will be Q4 values, hence, the highest 25% of numbers are:

                                              48 x 25% = 12

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In freefall, heavier objects fall with a greater acceleration than lighter objects.
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A block of mass 10.0 kg is pulled to the right along a rough horizontal surface with a constant horizontal force of 20.0 N. The
Yakvenalex [24]

Answer:

the magnitude of acceleration will be 1.50m/s^2

Explanation:

To calculate your acceleration, you can use your formula that states that the net force on an object is equal to the mass of the object multiplied by the acceleration of the object. Fnet=ma

if you draw out this situation and label the forces you will have your vector towards the right with a magnitude of 20.0N and then your friction vector will be pointing to the left (in other words, in the negative direction) (opposing the direction of movement) with a magnitude of 5.00N, with the 10.0 kg box in the middle.

The net force will be calculated using F1+F2=Fnet where your F1=20.0N and F2= -5.00N (since it is towards the negative direction).

you will find that Fnet=15.0N

With that, plug in the values you know to calculate the acceleration of the block:

Fnet=ma

(15.0N)=(10.0kg)a    from her you can divide both sides by 10 to isolate a:

1.50=a  (and now make sure to label the units of your answer)

a=1.50m/s^2 (which is the typical unit for acceleration)

7 0
3 years ago
A wire carrying a current of 26.9 A is bent into a circular arc with a radius of 0.6 cm that sweeps out 0.900 radians. What is t
melomori [17]

The magnetic field at the center of the arc is 4 × 10^(-4) T.

To find the answer, we need to know about the magnetic field due to a circular arc.

<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
  • According to Biot savert's law, magnetic field at the center of a circular arc is
  • B=(μ₀ I/4π)× (arc/radius²)
  • As arc is given as angle × radius, so

        B=( μ₀I/4π)×(angle/radius)

<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>

B=(μ₀ I/4π)× (0.9/0.006)

  = (10^(-7)× 26.9)× (0.9/0.006)

  = 4 × 10^(-4) T

Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.

Learn more about the magnetic field of a circular arc here:

brainly.com/question/15259752

#SPJ4

5 0
2 years ago
Two objects exert a gravitational force of 3 N on one another when they are 10 m apart. What would that force be if the distance
jeka94
Gravitational force = G ( m1 m2 ) / r²
3 = G ( m1 m2 ) / ( 10 )²x = G ( m1 m2 ) / ( 5 )²We shall divide those two equations:3 / x = 1/100 / 1/25 = 25 / 100 = 1 / 4x · 1 = 3 · 4x = 12Answer:C. 12 N
8 0
3 years ago
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