Answer:
D) The equilibrium lies far to the left
Explanation:
According to the law of mass action, the equilibrium constant K for the reaction at 373K can be calculated as follows:
K = ![\frac{[CO][Cl_{2}]}{[COCl_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5D%5BCl_%7B2%7D%5D%7D%7B%5BCOCl_%7B2%7D%5D%7D)
= 2.19×10^{-10}
([X] means = concentration of X)
This means that in the equilibrium the concentration of the reactant (that is in the denominator) will be much higher (around 10^{10} fold) than the concentrations of the products (that are in the numerator), and this means that the equilibrium lies far to the left (to the reactants side) as very small amount of product is being formed.
Answer:
Because it only needs one more electron to get to a full valence shell (8), so it really wants it and is pulling other electrons in. It also has to do with needing one more electron to fill the 2p shell. It is a small element which means its electrons are pulled tightly to the nucleus.
Hope this helps!
Explanation:
Answer:
Li and H
Explanation:
2Li(s)+2H2O(i)→2LiOH(aq)+H2(g) is full balanced
Answer:
the answer would be (A.) and (D.).
Explanation:
the reason for that being is because if calcium sulfate is a main component of plaster of paris you would need to find out what is in it that makes it the main component aka (the formula) therefore part of the answer is (A.). The other part of the answer was (D.) because you would need to find the amount of calcium sulfate that contain 12 grams of oxegeon atoms because you finding the answer to that could lead to the answer of what is the main component of plaster of Paris.
OILRIG:
Oxidation is loss (of electrons)
Reduction is gain (of electrons)
so...
The first one is an oxidation half-equation as the Sn loses electrons;
The second one is a reduction half-equation as the Cl₂ gains electrons
