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Over [174]
3 years ago
10

Calculate the mass (in grams) of cobalt that has the same number of atoms as 521 mg of silicon.

Chemistry
1 answer:
denis23 [38]3 years ago
8 0
The atomic mass of silicon is 28 g/mol.
Therefore, 521 mg or 0.521 g will be equivalent to;
  0.521/28 = 0.01861 mooles
Atomic mass of cobalt is 27 g/mol
According to Avogadro's law the mass of cobalt that will have the same atom as 52 mg of silicon will be ;
(0.01861 moles × 27) = 0.5024 g or 502.4 mg

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B its viscosity decreases
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3 0
3 years ago
Given a stock standard solution of concentration 0.200 M, calculate the volume in mL required to make up calibration standards o
guapka [62]

M1V1 = M2V2

.200 (.025) = 1.60 X 10 -2 (V2)

V2 = .315 L

1.60 x 10-2 M  in 315 mL

6 0
3 years ago
An object in space is made of gas and gives off light and heat energy. We can only see it at night. Which object is it? (2 point
strojnjashka [21]

Answer:

stars

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7 0
3 years ago
A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

3 0
3 years ago
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