All categories

3 years ago

PLEASE HELP ME WITH MY QUIZ!!!!

Physics

1 answer:

egoroff_w [7]3 years ago

6 0

Answer:

The answer is b the radiation of the suns electromagnetic waves

Explanation:

I took the Quiz to.

You might be interested in

Two small plastic spheres are given positive electrical charges. When they are 15.0 cm apart, the repulsive force between them h

Tems11 [23]

Answer:

a) q_1=q_2= 7.42*10^-7 C

b) q_2= 3.7102*10^-7 C , q_1 = 14.8*10^-7 C

Explanation:

Given:

F_e = 0.220 N

separation between spheres r = 0.15 m

Electrostatic constant k = 8.99*10^9

Find: charge on each sphere

part a

q_1 = q_2

Using coulomb's law:

F_e = k*q_1*q_2 / r^2

q_1^2 = F_e*r^2/k

q_1=q_2= sqrt (F_e*r^2/k)

Plug in the values and evaluate:

q_1=q_2= sqrt (0.22*0.15^2/8.99*10^9)

q_1=q_2= 7.42*10^-7 C

part b

q_1 = 4*q_2

Using coulomb's law:

F_e = k*q_1*q_2 / r^2

q_2^2 = F_e*r^2/4*k

q_2= sqrt (F_e*r^2/4*k)

Plug in the values and evaluate:

q_2= sqrt (0.22*0.15^2/4*8.99*10^9)

q_2= 3.7102*10^-7 C

q_1 = 14.8*10^-7 C

4 0

3 years ago

Read 2 more answers

A GPS receiver can tell you your exact latitude and longitude?

Dmitry_Shevchenko [17]

That is false. A GPS cant tell latitude and longitude

3 0

3 years ago

If you drop a bouncing ball from a height of 40 centimeters, explain why it can only bounce back up to a height of less than 40

iren2701 [21]

Answer:

Due to energy loss while collision ball will not reach to same height while if there is no energy loss then in that case ball will reach to same height

Explanation:

As we know that initially ball is held at height h = 40 cm

So here we can say that kinetic energy of the ball is zero and potential energy is given as

$U = mgH$

now when strike with the ground then its its fraction of kinetic energy is lost in form of other energies

So the ball will left rebound with smaller energy and hence it will reach to height less than the initial height

While if we assume that there is no energy loss during collision then in that case ball will reach to same height again

8 0

3 years ago

A 3.9 kg block is pushed along a horizontal floor by a force of magnitude 30 N at a downward angle θ = 40°. The coefficient of k

Luba_88 [7]

Answer:

The frictional force $F_{fri} =$ 6.446 N

The acceleration of the block a = 6.04 $\frac{m}{s^{2} }$

Explanation:

Mass of the block = 3.9 kg

$\theta = 40$ °

$\mu$ = 0.22

(a). The frictional force is given by

$F_{fri} = \mu R_{N}$

$R_{N} = mg \cos \theta$

$R_{N} =$ 3.9 × 9.81 × $\cos 40$

$R_{N} =$ 29.3 N

Therefore the frictional force

$F_{fri} =$ 0.22 × 29.3

$F_{fri} =$ 6.446 N

(b). Block acceleration is given by

$F_{net} = F - F_{fri}$

F = 30 N

$F_{fri}$ = 6.446 N

$F_{net}$ = 30 - 6.446

$F_{net}$ = 23.554 N

The net force acting on the block is given by

$F_{net} = ma$

23.554 = 3.9 × a

a = 6.04 $\frac{m}{s^{2} }$

This is the acceleration of the block.

8 0

3 years ago

Which type of force is used by your legs to pedal a bicycle?

Kay [80]

The answer is strong push. When you ride a bike, the pedals convert a vertical push from your legs into rotational motion for the wheels to turn.

8 0

3 years ago