<span>the deeper you go the more pressure...that's for depth</span>
Answer:
The load has a mass of 2636.8 kg
Explanation:
Step 1 : Data given
Mass of the truck = 7100 kg
Angle = 15°
velocity = 15m/s
Acceleration = 1.5 m/s²
Mass of truck = m1 kg
Mass of load = m2 kg
Thrust from engine = T
Step 2:
⇒ Before the load falls off, thrust (T) balances the component of total weight downhill:
T = (m1+m2)*g*sinθ
⇒ After the load falls off, thrust (T) remains the same but downhill component of weight becomes m1*gsinθ .
Resultant force on truck is F = T – m1*gsinθ
F causes the acceleration of the truck: F= m*a
This gives the equation:
T – m1*gsinθ = m1*a
T = m1(a + gsinθ)
Combining both equations gives:
(m1+m2)*g*sinθ = m1*(a + gsinθ)
m1*g*sinθ + m2*g*sinθ =m1*a + m1*g*sinθ
m2*g*sinθ = m1*a
Since m1+m2 = 7100kg, m1= 7100 – m2. This we can plug into the previous equation:
m2*g*sinθ = (7100 – m2)*a
m2*g*sinθ = 7100a – m2a
m2*gsinθ + m2*a = 7100a
m2* (gsinθ + a) = 7100a
m2 = 7100a/(gsinθ + a)
m2 = (7100 * 1.5) / (9.8sin(15°) + 1.5)
m2 = 2636.8 kg
The load has a mass of 2636.8 kg
The kinetic energy of 2.5 kg ball after collision is 27.09 J.
Answer:
Explanation:
In elastic collision, the sum of momentum of the objects before collision will be equal to the sum of momentum of the objects after collision.
We know that momentum is the product of mass and velocity acting on any object.
So, the conservation of energy in elastic collision leads to following equation:

Since, the momentum is conserved ,the kinetic energy will also be conserved in elastic collision. So

Since initial velocity for M1 ball is zero, then

and

So, on solving all the above equation, we get an equation for velocity and that is
=final velocity of ball with mass 2.5 kg

So kinetic energy will be 1/2 mv2
Kinetic energy of 2.5 kg ball is 
So the kinetic energy of 2.5 kg ball after collision is 27.09 J.
Answer:
In marine ecosystems, climate change is associated with concurrent shifts in temperature, circulation, stratification, nutrient input, oxygen content, and ocean acidification. There are also strong linkages between climate and species distributions, phenology, and demography.
Explanation:
Mark her brainliest
The change in momentum is 240 kgm/s
<u>Explanation:</u>
Given:
Force, F = 120N
Time, dt = 2 sec
Change in momentum, dP = ?
We know,

On substituting the value we get:

Therefore, change in momentum is 240 kgm/s