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3 years ago

To calculate how much rest energy an object contains, you multiply

Physics

1 answer:

Rina8888 [55]3 years ago

5 0

This is what e=mc² means.
So rest energy is RH side of equation that is its mass times speed of light squared.

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A pendulum is lifted and released, causing the pendulum to oscillate in

kap26 [50]

Answer:

D. Energy is converted between kinetic and gravitational potential energy.

Explanation:

8 0

1 year ago

Truck drivers approaching a steep hill that they must climb often increase their speed. What good does this do, if any?

Inga [223]

Um, this doesn't make any sense. By climbing a hill, you are decreasing your momentum and kinetic energy, so it slows you down. The only positive, is after you have climbed the hill, you have more potential energy, and it will be released once you go down the hill, but you will not be as fast as if you ignored the hill.

6 0

2 years ago

In a physics lab, light with a wavelength of 570 travels in air from a laser to a photocell in a time of 16.5 . When a slab of g

aliina [53]

Answer:

Wavelength is calculated as 213.9 nm

Solution:

As per the question:

Wavelength of light = 570 nm

Time, t = 16.5 ns

Thickness of glass slab, d = 0.865 ns

Time taken to travel from laser to the photocell, t' = 21.3

Speed of light in vacuum, c = $3\times 10^{8}\ m/s$

Now,

To calculate the wavelength of light inside the glass:

After the insertion of the glass slab into the beam, the extra time taken by light to cover a thickness t = 0.865 m is:

t' - t = 21.3 - 16.5 = 4.8 ns

Thus

$\frac{d}{\frac{c}{n}} - \frac{d}{v} = 4.8\times 10^{- 9}$

$\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}$

where

n = refractive index of the medium

v = speed of light in medium

$\frac{0.8656}{\frac{c}{n}} - \frac{0.865}{v} = 4.8\times 10^{- 9}$

$n = \frac{4.8\times 10^{- 9}\times 3.00\times 10^{8}}{0.865} + 1$

n = 2.66

Now,

The wavelength in the glass:

$\lambda' = \frac{\lambda }{n}$

$\lambda' = \frac{570}{2.66} = 213.9\ nm$

5 0

3 years ago

Where does the shadow of the shuttle in space form?

vekshin1

The shadow forms on the first surface away from the shuttle in the direction opposite the sun.

8 0

2 years ago

Young's experiment is performed with light of wavelength 502 nm from excited helium atoms. Fringes are measured carefully on a s

PSYCHO15rus [73]

Answer:

Explanation:

wave length of light λ = 502 nm

screen distance D = 1.2 m

width of one fringe = 10.2 mm / 20

= .51 mm

fringe width = λ D / a , a is separation of slits

Puting the values given

.51 x 10⁻³ = 502 x 10⁻⁹ x 1.2 / a

a = 502 x 10⁻⁹ x 1.2 / .51 x 10⁻³

= 1181.17 x 10⁻⁶ m

1.18 x 10⁻³ m

= 1.18 mm .

8 0

2 years ago