Answer:
The actual free energy = 78.54 X 10⁻² J
Explanation:
Given standard free energy = 23.8 kJ/mol
Free energy due to the presence of fructose 1,6-bisphosphate (1.4 X 10⁻⁵ M)
= 1.4 X 10⁻⁵ M * (23800 J/mol)
= 33.32 X 10⁻² J
Free energy due to the presence of glyceraldehyde 3-phosphate (3 X 10⁻⁶ M)
= 3 X 10⁻⁶ M * (23800 J/mol)
=7.14 X 10⁻² J
Free energy due to the presence of dihydroxyacetone phosphate (1.6 x 10⁻⁵M)
= 1.6 x 10⁻⁵M * (23800 J/mol)
= 38.08 X 10⁻² J
The actual free = 33.32 X 10⁻² J + 7.14 X 10⁻² J + 38.08 X 10⁻² J
The actual free energy = 78.54 X 10⁻² J
Answer:
i would say A-B
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The balanced chemical equation for the reaction is as follows;
Ca(OH)2 + 2HCl —> CaCl2 + 2H2O
The stoichiometry of Ca(OH)2 to HCl is 1:2.
Number of Ca(OH)2 moles reacted = 0.00100 mol
Therefore number of HCl moles that should react with base is double the amount of moles of base reacted.
Number of acid moles in 25.00 ml
= 0.00100 mol x2 = 0.00200 mol
Correct answer is 0.002 mol
<u>Answer:</u> The volume of oxygen gas is
<u>Explanation:</u>
To calculate the volume of the gas, we use the equation given by ideal gas equation:
where,
P = pressure of the gas = 5 MPa = 5000 kPa (Conversion factor: 1 MPa = 1000 kPa)
V = Volume of gas = 3.34 L
n = number of moles of oxygen gas = 1 mole
R = Gas constant =
T = Temperature of the gas = 200 K
Putting values in above equation, we get:
Hence, the volume of oxygen gas is