Question

24. The standard free energy of the aldolase reaction (in the reverse aldol direction) is 23.8 kJ/mol. The concentrations of the three metabolites in the hepatocyte are: fructose 1,6-bisphosphate (1.4 X 10-5 M), glyceraldehyde 3-phosphate (3 X 10-6 M) and dihydroxyacetone phosphate (1.6 x 10-5 M). Calculate the actual free energy of the reaction at 37 degrees C.

Answer 1

Answer:

The actual free energy = 78.54 X 10⁻² J

Explanation:

Given standard free energy = 23.8 kJ/mol

Free energy due to the presence of fructose 1,6-bisphosphate  (1.4 X 10⁻⁵ M)

= 1.4 X 10⁻⁵ M * (23800 J/mol)

= 33.32 X 10⁻² J

Free energy due to the presence of glyceraldehyde 3-phosphate (3 X 10⁻⁶ M)

= 3 X 10⁻⁶ M *  (23800 J/mol)

=7.14 X 10⁻² J

Free energy due to the presence of  dihydroxyacetone phosphate (1.6 x 10⁻⁵M)

= 1.6 x 10⁻⁵M *  (23800 J/mol)

= 38.08 X 10⁻² J

The actual free = 33.32 X 10⁻² J + 7.14 X 10⁻² J + 38.08 X 10⁻² J

The actual free energy = 78.54 X 10⁻² J