The layers of the fossil the oldest is usual the bottom layer,and the top layer is the newest layer
The best answer is that it reduces the level of ground water
Answer:
a) ![\Delta{t} = 5.39s](https://tex.z-dn.net/?f=%5CDelta%7Bt%7D%20%3D%205.39s)
b) the motorcycle travels 155 m
Explanation:
Let
, then consider the equation of motion for the motorcycle (accelerated) and for the car (non accelerated):
![v_{m2}=v_0+a\Delta{t}\\x+d=(\frac{v_0+v_{m2}}{2} )\Delta{t}\\v_c = v_0 = \frac{x}{\Delta{t}}](https://tex.z-dn.net/?f=v_%7Bm2%7D%3Dv_0%2Ba%5CDelta%7Bt%7D%5C%5Cx%2Bd%3D%28%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%20%29%5CDelta%7Bt%7D%5C%5Cv_c%20%3D%20v_0%20%3D%20%5Cfrac%7Bx%7D%7B%5CDelta%7Bt%7D%7D)
where:
is the speed of the motorcycle at time 2
is the velocity of the car (constant)
is the velocity of the car and the motorcycle at time 1
d is the distance between the car and the motorcycle at time 1
x is the distance traveled by the car between time 1 and time 2
Solving the system of equations:
![\left[\begin{array}{cc}car&motorcycle\\x=v_0\Delta{t}&x+d=(\frac{v_0+v_{m2}}{2}}) \Delta{t}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dcar%26motorcycle%5C%5Cx%3Dv_0%5CDelta%7Bt%7D%26x%2Bd%3D%28%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%7D%29%20%5CDelta%7Bt%7D%5Cend%7Barray%7D%5Cright%5D)
![v_0\Delta{t}=\frac{v_0+v_{m2}}{2}\Delta{t}-d \\\frac{v_0+v_{m2}}{2}\Delta{t}-v_0\Delta{t}=d\\(v_0+v_{m2})\Delta{t}-2v_0\Delta{t}=2d\\(v_0+v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\(2v_0+a\Delta{t})\Delta{t}-2v_0\Delta{t}=2d\\a\Delta{t}^2=2d\\\Delta{t}=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2*58}{4}}=\sqrt{29}=5.385s](https://tex.z-dn.net/?f=v_0%5CDelta%7Bt%7D%3D%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%5CDelta%7Bt%7D-d%20%5C%5C%5Cfrac%7Bv_0%2Bv_%7Bm2%7D%7D%7B2%7D%5CDelta%7Bt%7D-v_0%5CDelta%7Bt%7D%3Dd%5C%5C%28v_0%2Bv_%7Bm2%7D%29%5CDelta%7Bt%7D-2v_0%5CDelta%7Bt%7D%3D2d%5C%5C%28v_0%2Bv_0%2Ba%5CDelta%7Bt%7D%29%5CDelta%7Bt%7D-2v_0%5CDelta%7Bt%7D%3D2d%5C%5C%282v_0%2Ba%5CDelta%7Bt%7D%29%5CDelta%7Bt%7D-2v_0%5CDelta%7Bt%7D%3D2d%5C%5Ca%5CDelta%7Bt%7D%5E2%3D2d%5C%5C%5CDelta%7Bt%7D%3D%5Csqrt%7B%5Cfrac%7B2d%7D%7Ba%7D%7D%3D%5Csqrt%7B%5Cfrac%7B2%2A58%7D%7B4%7D%7D%3D%5Csqrt%7B29%7D%3D5.385s)
For the second part, we need to calculate x+d, so you can use the equation of the car to calculate x:
![x = v_0\Delta{t}= 18\sqrt{29}=96.933m\\then:\\x+d = 154.933](https://tex.z-dn.net/?f=x%20%3D%20v_0%5CDelta%7Bt%7D%3D%2018%5Csqrt%7B29%7D%3D96.933m%5C%5Cthen%3A%5C%5Cx%2Bd%20%3D%20154.933)
It is a reflecting telescope and a compound microscope. I know this for sure
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
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