Answer:
A. 6.282
B. 2.03kg
Explanation:
A.
We solve using archimedes principle
L³pwood = L²dwater
We make d subject of the formula
d = Lpwood/pester
= 18x651/1000
= 18x0.651
= 11.718cm
Distance from horizontal top to water level
= 18-11.718
= 6.282cm
B.
When we place lead block
WL + L³pwoodg = L³pwaterg
WL = L³g(Pwater-Pwood)
= 0.18³x9.8(1000-651)
= 19.94N
19.94/9.8
= 2.03kg
The mass m is therefore 2.03kg
Answer:
The correct option is "a plasma tail"
Explanation:
Gases <u>escaping from a comet</u> are ionized by ultraviolent rays from the sun. These ionized gases are then carried away from the sun by the solar wind to form the plasma tail. While the plasma tail is made up of gases, the dust tail is made up of tiny solid particles (dust) that escapes from the comet and are also pushed away from the sun.
Answer:
The magnitude of the electric field is 3.8 × 10⁵⁸ N/C and it is in the negative x- direction.
Explanation:
From work-kinetic energy principles, the kinetic energy change of the proton equals the work done by the electric field.
So, ΔK = W
1/2m(v₂² - v₁²) = qEd where m = mass of proton = 1.673 × 10⁻²⁷ kg, v₁ = initial speed of proton = 3.5 × 10⁶ m/s, v₂ = final speed of proton = 0 m/s, q = proton charge = + e = 1.602 × 10⁻¹⁹ C, E = electric field and d = distance moved by proton = x₂ - x₁ , x₁ = 20 cm and x₂ = 80 cm. So, d = 80 cm - 20 cm = 60 cm = 0.6 m
1/2m(v₂² - v₁²) = qEd
E = (v₂² - v₁²)/2mqd
substituting the values of the variables into E, we have
E = ((0 m/s)² - (3.5 × 10⁶ m/s)²)/(2 × 1.673 × 10⁻²⁷ kg × 1.602 × 10⁻¹⁹ C × 0.6 m)
E = - 12.25 × 10¹² m²/s² ÷ 3.22 × 10⁻⁴⁶
E = -3.8 × 10⁵⁸ N/C
So, the magnitude of the electric field is 3.8 × 10⁵⁸ N/C and it is in the negative x- direction.
Answer:
17.3 m
Explanation:
Given that,
Mass of a hammer is 0.58 kg
Velocity with which the hammer slides is 6.69 m/s at constant speed.
The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.
Putting all the values,
Neglecting negative value,
To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.
