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3 years ago

The p subshell can hold up to eight electrons in an atom (2 points) True or false?

Chemistry

2 answers:

hoa [83]3 years ago

8 0

Answer: The statement is false

Explanation:

Electrons occupy a region in atoms known as orbitals or subs hell. These orbitals include

I) S-orbital: it can occupy a maximum of two electrons

II) P-orbital: It occupies a maximum of six electrons

III) D-orbital: it occupies a maximum of ten electrons

F and G-orbitals as examples of other orbitals present.

A good illustration of the 6 electrons occupied by the P-subshell is seen in Sodium (Na) with atomic number of 11

Na = 1s2, 2S2 2p6, 3s1

Note: extra electrons are transferred to the next orbital

lawyer [7]3 years ago

8 0

Answer: This statement is false!!

Explanation: the p sub-shell can hold a max of 6 and the d sub-shell can hold a max of 10

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An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in

Advocard [28]

The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is Group 17, Period 2.

5 0

3 years ago

Consider the half reactions below for a chemical reaction.

ladessa [460]

Answer:

Option A:

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

Explanation:

The half reactions given are:

Zn(s) → Zn^(2+)(aq) + 2e^(-)

Cu^(2+) (aq) + 2e^(-) → Cu(s)

From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).

While in the second half reaction, Cu^(2+) is reduced to Cu.

Thus, for the overall reaction, we will add both half reactions to get;

Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)

2e^(-) will cancel out to give us;

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

7 0

2 years ago

A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo

lara [203]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

$\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M$

6 0

2 years ago

Carvone (C10H14O) is the main component of spearmint oil. It has a pleasant aroma and mint flavor. Carvone is often added to che

marta [7]

Answer: The mass of carbon in given amount of carvone is 47.52 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of carvone = 55.4 g

Molar mass of carvone = 150.22 g/mol

Putting values in equation 1, we get:

$\text{Moles of carvone}=\frac{55.4g}{150.22g/mol}=0.369mol$

The chemical formula of carvone is $C_{10}H_{14}O$

This contains 10 moles of carbon atom, 14 moles of hydrogen atom and 1 mole of oxygen atom

Now, calculating the mass of carbon in carvone from equation 1, we get:

Molar mass of carbon = 12 g/mol

Moles of carbon = (10 × 0.396) = 3.96 moles

Putting values in equation 1, we get:

$3.96mol=\frac{\text{Mass of carbon}}{12g/mol}\\\\\text{Mass of carbon}=(3.96mol\times 12g/mol)=47.52g$

Hence, the mass of carbon in given amount of carvone is 47.52 grams

6 0

3 years ago

Let’s assume that you put a balloon into the freezer. Initially,the balloon had 3.0liters of gas at a pressure of 400kPa and was

EastWind [94]

Here, we should use combined gas law which can be derived from combined gas law, “PV=nRT”. Rearranging, we can get PV/T=nR. Then we can set the two states in the problem together to get

P1V1/T1 = P2V2/T2

Then just plug in and solve algebraically.

Hope this helps

6 0

3 years ago