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Luba_88 [7]
2 years ago
12

A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i

s 6000 N, then the force exerted by the car on is truck is
Physics
1 answer:
LenKa [72]2 years ago
7 0

Answer:

Force exerted by car on truck will be 6000 N in opposite direction

Explanation:

It is given that mass of the car is one quarter of the mass of the truck

Force exerted by the truck on the car is 6000 N

We have to find the force exerted by car on the truck

According to newtons third law for any action there is equal and opposite reaction

So force exerted by car on the truck will be equal to 6000 N in opposite direction

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The Bragg's diffraction equation is :

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Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.

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Order of constructive interference, n =1

Substitute these value in equation (1).

1\times1.4\times10^{-10} =2d\sin20

d = 2.04 x 10⁻¹⁰ m

For second order constructive interference, let the Bragg's angle be θ₁.

Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).

2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}

\sin\theta_{1} =0.68

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In quantum mechanics, a central concept is that both matter and <u>energy</u> are alternate forms of the same entity and therefore both exhibit dual characteristics of particles and of <u>waves</u>.

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Find more information: brainly.com/question/17203857

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