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iogann1982 [59]
3 years ago
13

Name two things that would be different on our planet if we did not have a magnetic field.

Chemistry
2 answers:
Nookie1986 [14]3 years ago
7 0
Cosmic rays would be able to hit earth and birds wouldn't be able to migrate over the winter
Vaselesa [24]3 years ago
6 0
The planet would receive less solar radiation possibly eliminating auroras and would confuse animals sensitive to the earths magnetic field.
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What are the four abbreviations that are used to show the states of substances in chemical reactions?
Reil [10]
Answer: s (solid), l (liquid), g (gas), aq (Aqueous)

Aqueous is for when something has dissolved in water and given the symbol aq
4 0
3 years ago
The textbook procedure is asking you to dissolve 1 g of 3-nitrophthalic acid in hydrazine and only then to add the triethylene g
Ivenika [448]

Answer:

The reaction between 3-nitrophthalic acid and hydrazine is highly vigorous. Therefore, the answer is <em>option C</em>.

Explanation:

Triethylene glycol is a high-boiling solvent which necessarily used to contain the synthesis of luminol, which is obtained from the reaction between 3-nitrophthalic acid and aqueous hydrazine. However, this reaction is carried out at a very high temperature, the prior addition of triethylene glycol can allow sufficient reflux for the required completion time without evaporating the solvent fully.

Furthermore, Luminol is an organic compound used to detect metallic ions in Biology. For example, it is used to detect blood traces in forensic investigations.

7 0
3 years ago
What is true of an aqueous solution that is 15.0 percent HNO3 by mass?
djverab [1.8K]

Answer:

B. It contains 15.0 grams of HNO₃ per 100 grams of solution.

Explanation:

  • The percent of a solute in a solution is the mass of the solute (g) per 100 g of solution.

<em>So, an aqueous solution that is 15.0 percent HNO₃ by mass means that It contains 15.0 grams of HNO₃ per 100 grams of solution.</em>

6 0
4 years ago
Read 2 more answers
Why is it necessary for Agricultural student to study home science.​
sveta [45]

Answer:

Hope it's help uu.. thankuu

7 0
2 years ago
What is the entropy change for freezing 2.71 g of C2H5OH at 158.7 K? ∆H = −4600 J/mol. Answer in units of J/K.
Ira Lisetskai [31]

Answer:

-1.71 J/K

Explanation:

To solve this problem we use the formula

ΔS = n*ΔH/T

Where n is mol, ΔH is enthalpy and T is temperature.

ΔH and T are already given by the problem, so now we calculate n:

Molar Mass C₂H₅OH = 46 g/mol

2.71 g C₂H₅OH ÷ 46g/mol = 0.0589 mol

Now we calculate ΔS:

ΔS = 0.0589 mol * −4600 J/mol / 158.7 K

ΔS = -1.71 J/K

4 0
3 years ago
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