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3 years ago

What happens to the light rays when they hit the specimen?

Physics

1 answer:

pogonyaev3 years ago

4 0

Answer:

Explanation:

Ray of light when hits any specimen or object. The light is partially reflected, partially reflected and partially absorbed. It is never completed reflected, refracted or absorbed. Hence, the correct answer would be c.

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a student places 8 similar coins in a pile . the height of the pile of coins is 2.4 cm calculate the average thickness of one co

Anon25 [30]

Answer:

0.3 cm

Explanation:

$\frac{2.4}{8} \\ = 0.3$

7 0

3 years ago

A runner with a mass of 80kg accelerates from 0 to 9 m/s in 3 s find the net force

frosja888 [35]

So, first you find your acceleration which is 3m/s^2, using the acceleration formula.
Now set up your equation, F=ma, so put in the stuff, F=80kg·3m/s^2. Then solve your equation by multiplying, and you get F=240N, since newtons are your measurement.
Hope this helps

4 0

4 years ago

A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr

Zinaida [17]

Answer:

The initial speed of bullet is "164 m/s".

Explanation:

The given values are:

mass of bullet,

$m'=9.00 \ g$

or,

$=0.009 \ kg$

mass of wooden block,

$m=1.20 \ kg$

speed,

$s=0.390 \ m$

Coefficient of kinetic friction,

$\mu=0.20$

As we know,

The Kinematic equation is:

⇒ $v^2=u^2+2as$

then,

Initial velocity will be:

⇒ $u=v^2-2as$

$=v^2-2 \mu gs$

On substituting the given values, we get

⇒ $u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}$

$=\sqrt{-1.5288}$

$=1.23 \ m/s$

As we know,

The conservation of momentum is:

⇒ $mu=m'u'$

or,

⇒ Initial speed, $u'=\frac{mu}{m'}$

On substituting the values, we get

⇒ $=\frac{1.20\times 1.23}{0.009}$

⇒ $=\frac{1.476}{0.009}$

⇒ $=164 \ m/s$

3 0

3 years ago

Match the following

Fofino [41]

Answer:

1. b

2. d

3. e

4. c

5. a

Explanation:

These are just basic definitions. Let me know if you need further clarification.

7 0

3 years ago

What happens to the electrostatic force between two charged particles if the distance between them is doubled?

Stells [14]

According to Coulomb's Law , The size of the force varies inversely as the square of the distance between the two charges. So ,if the distance between the two charges is doubled, the electrostatic force will become weak by one fourth of the original force.

5 0

3 years ago