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LUCKY_DIMON [66]
2 years ago
15

What happens to the light rays when they hit the specimen?

Physics
1 answer:
pogonyaev2 years ago
4 0

Answer:

C

Explanation:

Ray of light when hits any specimen or object. The light is partially reflected, partially reflected and partially absorbed. It is never completed reflected, refracted or absorbed. Hence, the correct answer would be c.

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The acceleration of the car with the data in the table above would be
neonofarm [45]

The acceleration of the car would be 0.33 first and then it would be 0.17.

<u>Explanation:</u>

An applied force is a force that is applied to an object by an individual or another item. On the off chance that an individual is pushing a work area over the room, at that point there is an applied power following up on the article. The applied power is the power applied on the work area by the individual.

The net force applied to the object rises to the mass of the article increased by the measure of its acceleration. The net power following up on the soccer ball is equivalent to the mass of the soccer ball duplicated by its adjustment in speed each second (its acceleration).

6 0
2 years ago
What are 5 differences between Spring Tides and Neap Tides?
ad-work [718]

Spring Tides are formed by the constructive interference of bulges created by the moon and sun. Spring Tides occur when the Sun, Moon and the Earth are aligned. Neap Tides are formed by the destructive interference created by the moon and sun. Neap tides occur when the Sun, Moon, and Earth align to make a right angle.
4 0
3 years ago
A 2.0 m conductor is formed into a square and placed in the horizontal xy-plane. A magnetic field is oriented 30.0° above the ho
Gnesinka [82]

Answer:

\phi_B = 0.216 T m^2

Explanation:

As we know that the length of the conductor is given as

L = 2 m

now if it is converted into a square then we have

L = 4a

a = \frac{L}{4} = 0.5 m

now the are of the loop will be

A = a^2 = 0.5(0.5) = 0.25 m^2

now the magnetic flux is defined as

\phi_B = BAcos\theta

here we know

B = 1.0 T

\theta = 30.0^o

\phi_B = (1.0 T)(0.25 m^2)(cos30)

\phi_B = 0.216 T m^2

5 0
3 years ago
You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 252 N in the negative x di
pentagon [3]

(a) 252 N, opposite to the applied force

There are two forces acting on the refrigerator in the horizontal direction:

- the pushing force of 252 N, F, forward

- the frictional force, Ff, pulling backward

In this case, the refrigerator is not moving: this means that its acceleration is zero. According to Newton's second law, this also means that the net force acting on the refrigerator is also zero:

\sum F = ma = 0

So we have

F-F_f = 0

which means that the frictional force is equal in magnitude to the pushing force:

F_f = F = 252 N

and the direction is opposite to the pushing force.

(b) 334.8 N

The force that must be applied to the refrigerator to make it moving is equal to the maximum force of friction, which is given by:

F_{max} = \mu mg

where

\mu = 0.61 is the coefficient of static friction

m = 56 kg is the mass of the refrigerator

g = 9.8 m/s^2 is the acceleration of gravity

Substituting:

F_max = (0.61)(56 kg)(9.8 m/s^2)=334.8 N

6 0
3 years ago
19.
OLEGan [10]
I believe that it is C.
8 0
3 years ago
Read 2 more answers
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