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DENIUS [597]
3 years ago
7

What pressure, in millimeters of mercury (mm Hg), is equivalent to 2.13 atmospheres

Physics
1 answer:
Sati [7]3 years ago
6 0
The "Standard Atmosphere" is 760 mm Hg . 2.13 times that pressure is (2.13 x 760) = 1,618.8 mm Hg.
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A woman jogs 20 km in 4 hours, then another 10 km in 2 hours. What is her average speed?
murzikaleks [220]

Answer:

I think 5 km/h but I am not sure

4 0
3 years ago
How is the control group and experimental group different
zzz [600]
The control group is the independent variable and the experimental group is the dependent due to change during the experiment. The experimental group will usually rely on another variable in the experiment for change.
4 0
3 years ago
Which of these statements is most likely correct about the Nebular theory of formation of planets?
exis [7]
Correct answer is D.

Explanation:
A) is not correct answer because this type of theory can not become law. Laws are properties that are same in any part of universe. Nebular theory is not correct for every part of universe.

B) is not correct answer because this theory could be replaced if some evidence show that some other theory is more likely to be correct.

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3 years ago
A weatherman carried an aneroid barometer from the ground floor to his office atop the Sears Tower in Chicago. On the level grou
Sophie [7]

Answer:

442.36038 m or 1451.31362 ft

Explanation:

P_1 = Initial pressure = 30.15 inHg

P_2 = Final pressure = 28.607 inHg

\rho = Density of air  = 0.075 lb/ft³

1\ lb/ft^3=16.0185\ kg/m^3

1\ in=0.0254\ m

1\ m=3.28084\ ft

Density of mercury = 13560 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

Difference in pressure is given by

P_1-P_2=\rho gh\\\Rightarrow h=\frac{P_1-P_2}{\rho g}\\\Rightarrow h=\frac{(30.15-28.607)\times 13560\times 0.0254\times 9.81}{0.075\times 16.0185\times 9.81}\\\Rightarrow h=442.36038\ m\\\Rightarrow h=442.36038\times 3.28084\\\Rightarrow h=1451.31362\ ft

The height of the building is 442.36038 m or 1451.31362 ft

4 0
3 years ago
Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that
Pani-rosa [81]

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

........(1)

now, orbital velocity of satellite B

from equation 1

hence, the correct answer is option B

8 0
2 years ago
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