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Cerrena [4.2K]
3 years ago
15

A sound wave has a frequency of 628 Hz in air

Physics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

Answer is 257°C

Explanation:

Given

frequency = 628 Hz

wavelength = 0.49 m

speed of sound at 0°C = 325 m/s

Find

1.speed of sound at t °C=?

2.temperature = ?

Formula

speed of sound at t °C = speed of sound at 0°C   [1+t/273]

Solution

1. speed of sound at t °C = f*∧

                                        = 628*0.49

                                        =307.7m/s

2.speed of sound at t °C = speed of sound at 0°C   [1+t/273]

                    307.7 m/s    = 325 m/s [1+ t/ 273]

                    307.7/325   = 1+t/273

                    0.94             = 1+t/273

              multiplying 273 on both sides

                     (0.94)(273)  = 1+t/273 (273)

                      258             = 1+ t

                       258 - 1        = t

                             257°C    = t

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Answer:

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Explanation:

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3 years ago
How much heat is needed to warm 0.072kg of gold from 20 celsius and 90 celsius if the specific heat of gold 136 joules
dybincka [34]

Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.

Mass of the gold (m) = 0.072 kg

Temperature change (ΔT) = 90 - 20 = 70 degree Celsius

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Heat supplied = m × c × ΔT

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5 0
3 years ago
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Answer:

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Explanation:

this exercise you want to divide the rectangular room into two triangular rooms

                 

the area of ​​triangles is

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As the students will be learning different terms, definitions, methods and different subjects, they should be able to distinguish among different definitions as well as they should recall the things they have learnt. So the answers for the test questions will help to recall the topics learnt by the students while the matching concept will help the students to recognize each definition with their terms.

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Answer:

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