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Over [174]
3 years ago
10

Define the work Envelope for a Robot

Engineering
1 answer:
Masteriza [31]3 years ago
7 0
A robot's work envelope is its range of movement. It is the shape created when a manipulator reaches forward, backward, up and down. These distances are determined by the length of a robot's arm and the design of its axes. ... A robot can only perform within the confines of this work envelope.
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An amplifier with 40 dB of small-signal, open-circuit voltage gain, an input resistance of 1 MO, and an output resistance of 100
Vanyuwa [196]

convert 40db to standard gain

AL=10^40/20=100

calculate total voltage gain

=AL×RL/RL+Ri

=83.33

38.41 DB

calculate power

Pi=Vi^2/Ri Po=Vo^2/RL

power gain= Po/Pi

=13.90×10^6

3 0
3 years ago
you have a permanent magnet whit remanent induction. than you cut a piec of that magnet. if you put that piece back into permane
ELEN [110]
Yes, it will. The induction will be the same as long as it’s put back together.
5 0
4 years ago
As a general rule of thumb, the ratio of the rate of etch-product formation to the flow rate of etch gas should be greater than
g100num [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0
3 years ago
Differnce between boussinesqs and westergards theory of stress distribution of soil?​
arlik [135]
Boussinesq's influence factor is high Westergaard's theory:- 1. ) Assumes that the soil medium is anisotropic 2) Deals with thin sheets of rigid material sandwiched in a homogeneous medium. ... 5) Westergaard's influence factor is low compare to Boussinesq's influence factor.
7 0
2 years ago
Some aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 35 MPa m . It has bee
GaryK [48]

Answer:  Fracture will not occur since Kc (32.2 MPa√m) ∠ KIc (35  MPa√m).

Explanation:

in this question we are asked to determine if an aircraft will fracture for a given fracture toughness.

let us begin,

from the question we have that;

stress = 325 MPa

fracture toughness (KIc) = 35  MPa√m

the max internal crack length = 1.0 m

using the formula;

Y = KIc/σ√(πα)    ---------------(1)

solving for Y we have;

Y =  35 (MPa√m) / 250 (MPa) √(π × 2×10⁻3/2m)

Y = 2.50

so to calculate the fracture roughness;

Kc = Y × σ√(πα)   = 2.5 × 3.25√(π × 1×10⁻³/2) = 32.2 MPa√m

Kc = 32.2 MPa√m

From our results we can say that fracture will not occur since Kc (32.2 MPa√m) is less than KIc (35  MPa√m) of the material.

cheers i hope this helps!!!!

8 0
3 years ago
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