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yKpoI14uk [10]
4 years ago
12

you have a permanent magnet whit remanent induction. than you cut a piec of that magnet. if you put that piece back into permane

nt magnet will the remanent induction be the same it was in begining​
Engineering
1 answer:
ELEN [110]4 years ago
5 0
Yes, it will. The induction will be the same as long as it’s put back together.
You might be interested in
What is the impedance of a 5μF capacitor at a frequency of 500Hz? What is the impedance of a60mH inductor at this frequency?
choli [55]

Answer:

1) 63.66 ohm

2) 188.49 ohm

Explanation:

Data provided in the question:

Part 1

Capacitance, C = 5μF = 5 × 10⁻⁶ F

Frequency = 500 Hz

Now,

Impedance = \frac{1}{2\times\pi\times f\times C}

or

Impedance = \frac{1}{2\times\pi\times500\times5\times10^{-6}}

or

Impedance = 63.66 ohm

Part 2

Inductance = 60 mH = 60 × 10⁻³ H

Frequency = 500 Hz

Now,

Impedance for an inductor = 2πfL

thus,

Impedance = 2 × π × 500 × 60 × 10⁻³

= 188.49 ohm

4 0
3 years ago
Project 8:The Harris-Benedict equation estimates the number of calories your body needs to maintain your weight if you do no exe
lilavasa [31]

Answer:

See explaination and attachment for the program code and output

Explanation:

#include <iostream>

using namespace std;

int main()

{

char gender; //details for gender and checking

char ans;

do

{

cout<<"Gender (M or F): ";

cin>>gender;

switch(gender)

{

case 'M':

//cout<<"Male."<<endl;

break;

case 'F':

//cout<<"Female."<<endl;

break;

default:

cout<<"Wrong Gender. Please enter again (M or F): ";

cin>>gender;

}

int Weight,Height,Age; //declaration of variables

double bmr;

cout<<"Weight: ";

cin>>Weight;

cout<<"Height (in inches): ";

cin>>Height;

cout<<"Age: ";

cin>>Age;

//bmr calculations for male and female

if (gender = 'M')

{

bmr = 66 + (6.3 * Weight) + (12.9 * Height) - (6.8 * Age);

cout<<"He needs "<<bmr<<" to maintain his weight."<<endl;

cout<<"He needs to eat "<<(bmr/230)<< " candy bars in one day."<<endl;

}

else if (gender = 'F')

{

bmr = 655 + (4.3 * Weight) + (4.7 * Height) - (4.7 *Age);

cout<<"She needs "<<bmr<<" to maintain her weight"<<endl;

cout<<"She needs to eat "<<(bmr/230)<< " candy bars in one day."<<endl;

}

cout<< "Do you want to do another one>continue (Y/N): ";

cin >> ans;

}while(ans=='y'||ans=='Y');

cout<<"\n Thanks for using my BMR calculator. Good Bye!.";

return 0;

}

Kindly check attachment for output.

4 0
3 years ago
A circuit contains a 40 ohm resistor and a 60 ohms resistor connected in parallel. If you test this circuit with a DMM you shoul
lorasvet [3.4K]
<h2>Answer:</h2>

24Ω

<h2>Explanation:</h2>

When resistors are connected in parallel, the reciprocal of their combined resistance, when read with a DMM (Digital Multimeter - for measuring various properties of a circuit or circuit element such as resistance...) is the sum of the reciprocals of their individual resistances.

For example if two resistors of resistances R₁ and R₂ are connected together in parallel, the reciprocal of their combined resistance Rₓ is given by;

\frac{1}{R_x} = \frac{1}{R_1} + \frac{1}{R_2}

Solving for Rₓ gives;

R_{x} = \frac{R_1 * R_2}{R_1 + R_2}          ------------------(i)

From the question;

Let

R₁ = resistance of first resistor = 40Ω

R₂ =  resistance of second resistor = 60Ω

Now,

To get their combined or total resistance, Rₓ, substitute these values into equation (i) as follows;  

R_{x} = \frac{40 * 60}{40 + 60}

R_{x} = \frac{2400}{100}

R_{x} = 24 Ω

Therefore, the total resistance is 24Ω

4 0
3 years ago
1. A flywheel is suspended by resting the inside of the rim on a horizontal knife edge so that the wheel can swing in a vertical
sammy [17]

Answer: A fly wheel having a mass of 30kg was allowed to swing as pendulum about a knife edge at inner side of the rim as shown in figure.

Explanation:

8 0
3 years ago
A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm (0.60 in. × 0.75 in.) is pulled in tension with 44,500
lukranit [14]

Answer:

The resulting strain is 1.39\times 10^{-3}.

Explanation:

A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm

Force, F = 44,500 N

Th elastic modulus of Cu to be 110 GPa

The resulting strain is given by the formula as follows :

\epsilon=\dfrac{F}{AE}

E is elastic modulus of Cu is are of cross section

\epsilon=\dfrac{44500}{15.2\times 19.1\times 10^{-6}\times 110\times 10^9}\\\\\epsilon=1.39\times 10^{-3}

So, the resulting strain is 1.39\times 10^{-3}.

6 0
4 years ago
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